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PolarNik [594]
3 years ago
8

What is 2/3 dividend by 1/2?

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​
Mathematics
1 answer:
Ludmilka [50]3 years ago
7 0

Answer: one and one third 1 1/3

Step-by-step explanation:

2/3 divided 1/2

2/3•2/1

4/3 or 1 1/3

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PLEASE HELP <br> I forgot how to do this and it’s for a final :((
natima [27]
F(x)= 2/(x+1) and g(x)= -x2-12 => f(-7)= ? , g(2.5)= ?, g(f(- 0.5))= ?
In the expression of the function f(x) we will replace instead of x the number in bracket (-7) => f(-7) = 2/(-7+1)= 2/-6 = - 1/3
In the expression of the function g(x) we will replace instead of x number in bracket (2.5) => g(2.5) = - (2.5)squared -12= - 6.25 -12= - 18.25
Expression f(g(x)) or g(f(x)) is multiplication (composition) of the reflecting of functions f and g. We will do this in the following way => g(f(x))= g(2/(x+1))= -(2/(x+1))2 - 12= -(4/(x+1)2) -12= -4-12(x+1)2/(x+1)2=> we will replace instead of x the number in bracket (-0.5) or (-1/2) => g(f(-1/2) = -4-12((-1/2)+1)2/ ((-1/2+ 1)2= -4-12(1/2)2/(1/2)2=-4-12*(1/4)/(1/4)= (-4-3)/(1/4)=-28 
Eaisier way => f(-1/2)=2/((-1/2)+1)=2/(1/2)= 4  g(4) -(4)2-12 = -16-12= -28





8 0
4 years ago
Describe the line.(what kind of line is it?)​
adelina 88 [10]

Answer:

slope it's a slope and I need 20 characters

8 0
3 years ago
Read 2 more answers
What is the period of the graph of the equation y = a sin bx?
steposvetlana [31]

T=2π/|b|. The period of an equation of the form y = a sin bx is T=2π/|b|.

In mathematics the curve that graphically represents the sine function and also that function itself is called sinusoid or sinusoid. It is a curve that describes a repetitive and smooth oscillation. It can be represented as y(x) = a sin (ωx+φ) where a is the amplitude, ω is the angular velocity with ω=2πf, (ωx+φ) is the oscillation phase, and φ the initial phase.

The period T of the sin function is T=1/f, from the equation ω=2πf we can clear f and substitute in T=1/f.

f=ω/2π

Substituting in T=1/f:

T=1/ω/2π -------> T = 2π/ω

For the example y = a sin bx, we have that a is the amplitude, b is ω and the initial phase φ = 0. So, we have that the period T of the function a sin bx is:

T=2π/|b|

7 0
3 years ago
What’s the measure of angle c?<br><br><br> Some please answer fast. Please.
kow [346]

Answer: 42

Step-by-step explanation:

Ok what you want to do is add all of them up and equal it to 180 because a triangle is 180 degrees .

Your equation should look like this

9x-3+22x+1+42-3x = 180

What you want to do first is combine all the x and numbers on the left side so it should look like this

1) 28x+40= 180

Then you want to subtract 40 on both sides so it will look like this

2)28x=140

You want to get x by it self so you divide 28 on both sides

3) x=140/28

4) x=5

Since you are finding c you have to insert 5 into x

1) 9(5)-3

2)45-3

Then your answer should be 42

6 0
3 years ago
Formúla General <br>a) 4x²=9x-2=0 <br><br>b) X²+8x-84=0<br>​
makkiz [27]

Answer:<em> </em><em>a)</em> x=\dfrac{-9 \pm\sqrt{113} }{8}

             <em> b) x₁ = - 14; x₂ = 6.</em>

Step-by-step explanation:

a) 4x² + 9x - 2 = 0

x=\dfrac{-b \pm \sqrt{b^{2}-4ac } }{2a} \\\\a=4; \: \: b=9; \: \: c=-2\\x =\dfrac{-9 \pm \sqrt{9^{2}-4 \cdot 4 \cdot (-2) } }{2 \cdot 4} =\dfrac{-9 \pm\sqrt{113} }{8}

b) x² + 8x - 84 = 0

x=\dfrac{-b \pm \sqrt{b^{2}-4ac } }{2a} \\\\a=1; \: \: b=8; \: \: c=-84\\\\x =\dfrac{-8 \pm \sqrt{8^{2}-4 \cdot 1 \cdot (-84) } }{2 \cdot 1} =\dfrac{-8 \pm\sqrt{400} }{2}=\dfrac{-8 \pm 20}{2} =-4 \pm 10\\\\x_{1} =-14\\x_{2} =6

7 0
3 years ago
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