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777dan777 [17]
3 years ago
8

100 points and beainliest due yesterday

Mathematics
1 answer:
Sedbober [7]3 years ago
8 0

Answer:

The relation is discrete function

Domain is  {x|x = 2,2,2}

Range is {y|y = 4, -1, -3}

Step-by-step explanation:

I. This function is discrete because x = 2,2,2

and y = 4, -1, -3

Or (2,4), (2,-1) and (2,-3)

If this function is continuous, the x and y will be something like this -3 <= x <= 3

II. Domain is x.value

III. Range is y.value

Ask me for anything.

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-7(5h + 9) = 17 - 8h please help i need this FAST
Katyanochek1 [597]

Answer:

h = -2 \frac{26}{27}

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

4 0
2 years ago
Read 2 more answers
One cubic meter of water weighs approximately 2200 pounds. There are 100 cm in one meter. If you have a box-shaped fish tank tha
Diano4ka-milaya [45]

Answer:

158.4 pounds

Step-by-step explanation:

first find the volume of the tank

V = 30 \times 30 \times 80

V = 72000 cm^3

to convert this to m^3 we know that 1m = 100cm

V = 72000 cm^3 \times \left(\dfrac{1\,\text{m}}{100\,\text{cm}}\right)^3

V = 72000 cm^3 \times \left(\dfrac{1\,\text{m}^3}{100^3\,\text{cm}^3}\right)

the cm^3 cancel out.

V = \dfrac{72000}{100^3} m^3

V = 0.072\,m^3

by simply converting the side-lengths to meters beforehand can give you this answer directly:

V = 0.3 \times 0.3 \times 0.8 = 0.072 m^3

it is given that 1 meter cube of water weighs about 2200 pounds.

1\,m^3 = 2200 \,\text{lb}

multiply both sides with 0.072 to find our answer:

1\,m^3 \times 0.072 = 2200 \times 0.072 \,\text{lb}

0.072\,m^3 = 158.4 \,\text{lb}

hence the weight of the water in the tank would be 158.4 pounds!

3 0
3 years ago
What is the equation of the following line written in general form? (The y-intercept is -1.)
Strike441 [17]
2x-y-1=0

There are 2 ways that you can solve this . Either plug in the x and y value into each equation until it is right or rewrite the equation .
the equation in slope intercept form is y=2x-1
When you get y by itself in the last one it is also equal to y=2x-1
For both ways work is attached !

5 0
2 years ago
What is the distance between point (7,9) and point (-2,7)
skad [1K]

Answer:

9.21954445729

Step-by-step explanation:

use distance formula

3 0
2 years ago
Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m
GalinKa [24]

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

d=\sqrt{\frac{3h}{2} }

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)

For Addison h=85(1/3)

d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)

Subtracting both distances we get

8\sqrt{2}-6\sqrt{2}  =2\sqrt{2}

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

5 0
2 years ago
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