3 years ago

(6^5)^-2 please get it right

Mathematics

1 answer:

Verizon [17]3 years ago

6 0

Answer:

$\frac{1}{ {6}^{10} }$

Step-by-step explanation:

$( {6}^{5} {)}^{ - 2}$

${6}^{5 \times ( - 2)}$

${6}^{ - 10}$

$= \frac{1}{ {6}^{10} }$

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Pls help I dont understand. Find the inverse of this function.

lisov135 [29]

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$g(x) = \sqrt[3]{x} - 3 \\ \\ x = \sqrt[3]{y} - 3 \\ \sqrt[3]{y} = x + 3 \\ y = {(x + 3)}^{3} \\ y = {(x + 3)}^{2} (x + 3) \\ y = ({x}^{2} + 6x + 9)(x + 3) \\ \\ y = {x}^{3} + 6 {x}^{2} + 9x + 3 {x}^{2} + 18x + 27 \\ \\ y = {x}^{3} + 9 {x}^{2} + 27x + 27 \\ \\ \\ g(x)^{ - 1} = {x}^{3} + 9 {x}^{2} + 27x + 27$

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