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Alexxx [7]
3 years ago
10

3.29<___

Mathematics
1 answer:
Drupady [299]3 years ago
3 0

Answer:

3.29 is less than 3.4

D. 3.4

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I will give a thanks 5 stars and i will give you the brainliest Gwen mows 1/4 acre in 3/4 hours. what fraction is used to find t
Vinil7 [7]

Answer:

D

Step-by-step explanation:

4 0
3 years ago
2. A soccer field is bordered on three sides by a parking lot of width x. The total
notsponge [240]

Answer: 50m

Step-by-step explanation:

this is the logical way I solved it:

1. Find the area of the entire area thing

300*200=60000

2. Subtract the area of the field from the area of the entire place

60000-30000=30000

3. Divide the area of the parking by three because there are three sides

30000 ÷ 3 = 10000

4. Divide 10000 by 200, not 300 because we want to find the side with one <em>x</em>, not two <em>x</em> (there are two sides adding on to the side with 300, but only one side on the side with 200)

10000÷200= 50

I know the steps are weird, but I know this is the right answer because this was on the unit test (same misspelling and everything lol) and during tutoring my teacher showed me how to do it, but of course I had to forget the steps.

4 0
3 years ago
Solve 2-x=5x+1<br> Find x
Nady [450]

Answer:

Collect like term

2-1=5x+x

1=6x

6x=1

divide both side by 6

x=1/6

5 0
3 years ago
Read 2 more answers
For the class of 2013's prom Norman's dress shop sold cheaper dresses for $90 each and more expensive dresses for $140 each. The
Tema [17]

Answer:

Number of cheaper dresses sold  is 35

Number of expensive  dresses sold  is 15

Step-by-step explanation:

Given:

Cost of cheaper dresses = $90

Cost of  expensive dresses = $140

Total cost of  the dresses = $5250

To Find:

Number of cheaper dress = ?

Number of expensive  dress = ?

Solution:

Let

The number of  cheaper dresses be x

The number of  expensive dresses be y

(Number of cheaper dresses X cost of cheap dress) +  (Number of Expensive dresses X cost of  expensive dress)  =  $5250

x \times90 +y \times 140 = 5250=  $5250

It is given that the 20 more of the cheaper dresses than the expensive dresses is sold

So,

number of cheaper dress  =  20  +  number of expensive dress

x = 20 + y---------------------------------------(1)

(20+y) \times90 +y \times 140 = 5250 = 5250

(20 \times 90 +y\times 90) +y \times 140= 5250

1800 + 90y+ 140y = 5250

1800 + 230y = 5250

230y =5250 -1800

230y = 3450

y = \frac{3450}{230}

y = 15

Substituting y in (1)

x = 20 +15

x= 35

5 0
4 years ago
Solve for x. <br><br> 3x/6 + 2 = 8<br><br> x = 3<br> x = 12<br> x = 24
Advocard [28]

\frac{3x}{6}  + 2 = 8  \\  \frac{3x}{6}  = 8 - 2 \\  \frac{3x}{6}  = 6 \\ 3x  = 36 \\ x = 36 \div 3 \\ x = 12
So; the answer is: 12
8 0
3 years ago
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