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Margarita [4]
3 years ago
14

A discounted concert ticket is $14.50 less than the original price p. You pay $53 for a discounted ticket. Write and solve an eq

uation to find the original price.
Mathematics
1 answer:
drek231 [11]3 years ago
4 0
Equation: Original price = cost of discounted ticket + discount

Original price = 53.00 + 14.50
Original price = 67.50
$67.50
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A rotating water toy sprays a steady stream of water that is 12 feet long. If the water toy makes a full rotation, what is the a
leonid [27]
75.4 
12 would be considered the radius 
C = 2 pi R
so just insert that into the formula and the answer should be 
75.39 but if you round up it would be 75.4 
5 0
2 years ago
Solve for x in the equation x squared + 11 x + StartFraction 121 Over 4 EndFraction = StartFraction 125 Over 4 EndFraction.
Ira Lisetskai [31]

Answer:

Below

Step-by-step explanation:

● x^2 + 11x + 121/4 = 125/4

Substract 125/4 from both sides:

● x^2 + 11x + 121/4-125/4= 125/4 -125/4

● x^2 + 11x - (-4/4) = 0

● x^2 +11x -(-1) = 0

● x^2 + 11 x + 1 = 0

This is a quadratic equation so we will use the determinanant (b^2-4ac)

● a = 1

● b = 11

● c = 1

● b^2-4ac = 11^2-4*1*1 = 117

So this equation has two solutions:

● x = (-b -/+ √(b^2-4ac) ) / 2a

● x = (-11 -/+ √(117) ) / 2

● x = (-11 -/+ 3√(13))/ 2

● x = -0.91 or x = -10.9

Round to the nearest unit

● x = -1 or x = -11

The solutions are { -1,-11}

6 0
3 years ago
Read 2 more answers
3. The image shows a circle with center (4, 6) and radius 10 units.
ICE Princess25 [194]

Answer:

(x - 4)^2 + (y - 6)^2 = 100

6 0
2 years ago
Calculating the Volume of a Sphere Given Diameter What is the volume of a sphere with a radius of 3/2 feet? The volume is Pi ft3
Angelina_Jolie [31]

14.14 ft³

Plug in 3/2 in the formula, which is \frac{4}{3} \pi r^3

8 0
2 years ago
Company ABC produces widgets. They have found that the cost, c (x), of making x widgets is a quadratic function in terms of x. T
Dahasolnce [82]

The given function  is a quadratic equation. Any quadratic equation can be written in the form :

C(x)=ax^{2}+bx+c

The given points can be taken as (2,23) ,(4,55) and(10,247)

We form three equations with the given points

For point (2,23 ) the equation is

23   = 4a + 2b + c

For point (4,55) the equation is

55 = 16a + 4b + c

For point  (10,247) the equation is:

247 = 100a+10b+c.

Solving the three equations for a,b,c we have :

32 = 12a + 2b

  16 = 6a + b

and,

 192 = 84 a + 6b

 32 = 14a + b

Solving for a,b,c we have:

a=2  b=4   c=7

The quadratic equation is c(x)=2x^{2}+4x+7.

When x=8

c(x)=2(8)^{2}+4(8)+7= 167.]

Option C. $167 is the right answer.



8 0
3 years ago
Read 2 more answers
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