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Mamont248 [21]
3 years ago
10

The actual distance between two villages is 120 km. On a map of the area, 0.5 cm represents 2 km. What is the actual distance be

tween the villages on the map?
Mathematics
2 answers:
Oduvanchick [21]3 years ago
8 0
On the map, the distance between the villages is 30 cm.
Since .5 cm represents 2 km, each cm on the map represents 4 km in actual distance, so to find the distance on the map, you divide 120 by 4 and you get 30. 
An alternative way to think of it is to set up a proportion. 
First, you would do .5/2 equals x/120
Next, you would cross multiply and get 2x equals 60
Then, you would solve and get x equals 30 
Your answer is 30 cm
otez555 [7]3 years ago
6 0
If .5cm is 2km, then 1 cm is 4 km, and therefore 120/4 is 30, so 30 centimeters on the map
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What is one eighth times three fourths
12345 [234]

Answer: 3/32

Step-by-step explanation:

1/8 * 3/4

8 * 4 = 32

1 * 3 = 3

3/32

5 0
3 years ago
Read 2 more answers
Suppose C is a 3 x 3 matrix such that det (C) = 4. Show that det (C+C) is equal to 32
Ber [7]

Step-by-step explanation:

Let's consider C is a matrix given by

\left[\begin{array}{ccc}a&b&c\\d&e&f\\g&h&i\end{array}\right]

them determinant of matrix C can be written as

\begin{vmatrix}a & b & c\\ d & e & f\\  g & h & i \end{vmatrix}\ =\ 4.....(1)

Now,

det (C+C)\ =\ \begin{vmatrix}a & b & c\\ d & e & f\\  g & h & i \end{vmatrix}\ +\ \begin{vmatrix}a & b & c\\ d & e & f\\  g & h & i \end{vmatrix}

                  =\ \begin{vmatrix}2a & 2b & 2c\\ 2d & 2e & 2f\\  2g & 2h & 2i \end{vmatrix}

                   =\ 2\times 2\times 2\times \begin{vmatrix}a & b & c\\ d & e & f\\  g & h & i \end{vmatrix}

                   =\ 8\times 4\ \ \ \ \ \ \ \         from\ eq.(1)

                    = 32      

Hence, det (C+C) = 32

7 0
3 years ago
What is the answer to this please show work
MatroZZZ [7]
The picture contains two geometric objects: semicircle and right triangle

First, find the area of semicircle
This is the formula for area of semicircle
a = 1/2 × area of circle
a = 1/2 × π × r²

Before we find the area, we should determine the value of r. Given from the question that the diameter is equals to 8 m. Radius (r) is half of diameter (d)
r = 1/2 d
r = 1/2 × 8
r = 4 m

Caculate the area
a = 1/2 × π × r²
a = 1/2 × 3.14 × 4²
a = 1/2 × 3.14 × 16
a = 1/2 × 50.24
a = 25.12 m²

Second, find the area of the right triangle
The formula is
a = 1/2 × b × h

Given from the question that the base (b) is 12 m, and the height (h) is 8 m.

Calculate the area, input the value of b and h to the formula
a = 1/2 × b × h
a = 1/2 × 12 × 8
a = 1/2 × 96
a = 48 m²

Third, sum both area
a = area of semicircle + area of right triangle
a = 25.12 + 48
a = 73.12 m²

Solution:
The area is 73.12 m²
5 0
3 years ago
Franklin has a five-dollar bill and d dimes in his money jar. Which expression could represent the value, in dollars, in frankli
solniwko [45]

Answer:

5+0.10d

Step-by-step explanation:

A five dollar bill is worth $5 and a dime is worth 10 cents, or a tenth of a dollar. To find the value of the money take the sum of the value of the bill and the number of dimes (d) times the value of each dime. You will get $5+0.10d.

If you would like FREE tutoring in algebra or another subject, check out www.growthinyouth.org.

8 0
3 years ago
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ddd [48]

Answer:

Odds against the events are 7/9.

Step-by-step explanation:

It is given that:

Odds in favor of event = 2 : 9 or 2/9

Let,

These odds are out of 1.

The odds against the event would be

Odds against = 1 - 2/9

Odds against = \frac{9-2}{9}

Odds against = \frac{7}{9}

Therefore,

Odds against the events are 7/9.

5 0
3 years ago
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