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aleksley [76]
3 years ago
11

What is 56(x+12+4) simplified

Mathematics
2 answers:
spayn [35]3 years ago
8 0
The answer is:  " 56x + 896 "  .
____________________________________
First, simplify the:

(x + 12 + 4) = (x + 16) ;

56(x + 12 + 4) =

56(x + 16) ;
_________________________
Note the distributive property of multiplication:

a(b + c) = ab + ac ;

a (b - c) = ab -  ac ;
_________________________

So;
_________________________
56(x + 16) =

56*x  +  56*16  =

56x + 896
________________________
Evgen [1.6K]3 years ago
5 0
The answer:


56 × (x + 15)
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58 more ml

Step-by-step explanation:

147-89=58 ml.

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What does the equation 7x^2-3y^2-x+2y+4=0 represent
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that's why circle is the answer

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Step-by-step explanation:

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3 years ago
Find The art length of a sector with an area of 8 square units.
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\bf \textit{arc's length}\\\\&#10;s=\cfrac{\theta \pi r}{180}\quad &#10;\begin{cases}&#10;r=radius\\&#10;\theta =angle~in\\&#10;\qquad degrees\\&#10;------\\&#10;\theta =\frac{180}{\pi }\\&#10;r=4&#10;\end{cases}\implies s=\cfrac{\frac{180}{\underline{\pi} }\underline{\pi} \cdot 4}{180}\implies s=\cfrac{\underline{180}\cdot 4}{\underline{180}}&#10;\\\\\\&#10;\boxed{s=4}

if you do a quick calculation on what that angle is, you'll notice that it is exactly 1 radian, and an angle of 1 radian, has an arc that is the same length as its radius.

that's pretty much what one-radian stands for, an angle, whose arc is the same length as its radius.
6 0
3 years ago
What is the equation of the oblique asymptote?<br> h(x) = x² – 3x - 4/x + 2
NNADVOKAT [17]

Simplifying h(x) gives

h(x) = (x² - 3x - 4) / (x + 2)

h(x) = ((x² + 4x + 4) - 4x - 4 - 3x - 4) / (x + 2)

h(x) = ((x + 2)² - 7x - 8) / (x + 2)

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An oblique asymptote of h(x) is a linear function p(x) = ax + b such that

\displaystyle \lim_{x\to\pm\infty} h(x) - p(x) = 0

In the simplified form of h(x), taking the limit as x gets arbitrarily large, we obviously have -22/(x + 2) converging to 0, while x - 5 approaches either +∞ or -∞. If we let p(x) = x - 5, however, we do have h(x) - p(x) approaching 0. So the oblique asymptote is the line y = x - 5.

4 0
2 years ago
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