First, you would distribute 2 into the parentheses so you would have 6x-8= 5x+6. Subtract 5x from both sides so you have x-8=6. Finally, add 8 to both sides which leaves you with x= 14
Answer: Choice B) I and II only
The mean and median are considered measures of center as they represent the average of a data set. The average basically being a point that collectively speaks for all of the data. For example, if you have a group of basketball players whose heights range from 5'11" to 6'9", then there is no single height to report; however, we can compute the average to get a basic idea of the single height. The interquartile range (IQR) is a measure of variability or spread of the data. The higher the IQR, the more spread out the data is. Recall that 50% of the data is represented by the IQR and that IQR = Q3 - Q1 where Q1 and Q3 are the first and third quartiles respectively. So because the IQR is a measure of spread, it is not considered a center point.
Simplify the following:
(5 i^3 t^4)/7 - 2
i^3 = i^2×i = (-1) i = -i:
(5×-i t^4)/7 - 2
Put each term in (5 (-i) t^4)/7 - 2 over the common denominator 7:
(5 (-i) t^4)/7 - 2 = (-5 i t^4)/7 - 14/7:
(-5 i t^4)/7 - 14/7
(-5 i t^4)/7 - 14/7 = (-5 i t^4 - 14)/7:
Answer: (-5 i t^4 - 14)/7
Answer:15+2.50(10x3)=x
Step-by-step explanation:
