Answer:
s = 22.5 m
Step-by-step explanation:
the equation for the speed change of a coach moving along a straight section of the road and starting braking at a speed of 20 m / s has the form v (t) = 25-5t. Using integral calculus, determine the coach's braking distance.
v (t) = 25 - 5 t
at t = 0 , v = 20 m/s
Let the distance is s.
Let at t = t, the v = 20
So,
20 = 25 - 5 t
t = 1 s
So, s = 25 x 1 - 2.5 x 1 = 22.5 m
Answer:
ok.... what is the question here....?? ;-;
Step-by-step explanation:
<7 and <10 are each 84 degrees
No. I can’t. Just wanting to get some points man, 5 would be nice.
Answer:
y = x + 15
Step-by-step explanation:
okay so you're gonna use the y2-y1/x2-x1 formula to find the slope (m)
24 - 19/9 - 4 = 5/5 = 1
so that is your slope (m)
and now if you follow your slope then you should get your y-intercept (b)
4 - 1 = 3 19 - 1 = 18
(3, 18)
3 - 1 = 2 18 - 1 = 17
(2, 17)
2 - 1 = 1 17 - 1 = 16
(1, 16)
1 - 1 = 0 16 - 1 = 15
(0, 15)
so thats your y-intercept (b)
and the equation will look like:
y = mx + b y = x + 15 or y = 1x + 15 (but the 1 isn't necessary)
