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pickupchik [31]
3 years ago
5

Help pls 20 points I will give brainleyest

Mathematics
2 answers:
mihalych1998 [28]3 years ago
7 0

Answer:

1. ascending

2. descending

Maslowich3 years ago
4 0

Answer:

1. Ascending Order

2. Descending Order

Step-by-step explanation:

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solniwko [45]

We have this equation:

\log(x) + \log(x + 99) = 2

First, combine both logarithms using the multiplication property and simplify the expression.

\log[x(x + 99)] = 2

\log[ {x}^{2} + 99x ] = 2

Now, use the definition of logarithm to transform the equation.

{10}^{2}  =  {x}^{2}  + 99x

{x}^{2}   +  99x  -  100 = 0

Finally, use the quadratic formula to solve the equation.

x =  \frac{ -99 ± \sqrt{ {99}^{2}  - 4 \times 1 \times ( - 100)} }{2 \times 1}

With this, we can say that the solution set is:

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We cannot choose x = -100 as a solution because we cannot have a negative logarithm. The only solution is x = 1.

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What is the solution to 0= -6n
HACTEHA [7]

The solution is 6=n

6+0=6+(-6)n

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Is the number zero 0 an integer?
Lyrx [107]

Yep! It is an integer!

Any negative, positive number or 0 is an integer.

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Step-by-step explanation:

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