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3 years ago

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Two towns are 480km apart. Two buses start at the same time from these two towns towards one another and they pass each other af

ter 6 hours. If the speed of one of the buses is 6km/hr more the speed of the other, find the speed of the buses.

1 answer:

Neporo4naja [7]3 years ago

5 0

Answer:

10number for a is a answer of that question

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Samuel measured three ropes as 3and 63/80 feet, 3and 1/5 feet, and 3and 11/20feet. Put the measurements of the ropes in order fr

S_A_V [24]

3 1/5, 3 11/20, 3 63/80

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3 years ago

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Suppose y varies directly as x and y=36 when x=4 find y when x=11

yarga [219]

It equals 99. 4 times 9 equals 36. 11 times 9 equals 99.

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3 years ago

Irina rode her bike to work at an average speed of 16 miles per hour. It started to rain, so she got a ride home along the same

Sedaia [141]

Answer:

0.7 hours

Step-by-step explanation:

Given that Irina was able to make the same distance from work to home in 0.4 of an hour at 27 miles per hour, we can use this rate and time to find the distance she travels to and from work using the general formula:

d = rt, where d=distance, r = rate and t = time

d = 27(0.4) = 10.8 miles

Since the distance from Irina's home to work is 10.8 miles, we can again use the formula 'd = rt' to find the time it takes her to bike to work at a rate of 16 miles per hour and solving for time, 't':

10.8 = (16)t

t = 0.7 hours

3 0

3 years ago

Data is collected to compare two different types of batteries. We measure the time to failure of 12 batteries of each type. Batt

-Dominant- [34]

Using the t-distribution, it is found that since the <u>test statistic is greater than the critical value for the right-tailed test</u>, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

At the null hypothesis, it is <u>tested if it does not outlast by more than 2 hours</u>, that is, the subtraction is not more than 2:

$H_0: \mu_B - mu_A \leq 2$

At the alternative hypothesis, it is <u>tested if it outlasts by more than 2 hours</u>, that is:

$H_1: \mu_B - \mu_A > 2$

The sample means are: $\mu_A = 8.65, \mu_B = 11.23$

The standard deviations for the samples are $s_A = s_B = 0.67$

Hence, the standard errors are:

$s_{Ea} = S_{Eb} = \frac{0.67}{\sqrt{12}} = 0.1934$

The distribution of the difference has <u>mean and standard deviation</u> given by:

$\overline{x} = \mu_B - \mu_A = 11.23 - 8.65 = 2.58$

$s = \sqrt{s_{Ea}^2 + s_{Eb}^2} = \sqrt{0.1934^2 + 0.1934^2} = 0.2735$

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{s}$

In which $\mu = 2$ is the value tested at the hypothesis.

Hence:

$t = \frac{\overline{x} - \mu}{s}$

$t = \frac{2.58 - 2}{0.2735}$

$t = 2.12$

The critical value for a <u>right-tailed test</u>, as we are testing if the subtraction is greater than a value, with a <u>0.05 significance level</u> and 12 + 12 - 2 = <u>22 df</u> is given by $t^{\ast} = 1.71$

Since the <u>test statistic is greater than the critical value for the right-tailed test</u>, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

A similar problem is given at brainly.com/question/13873630

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2 years ago

19. The bases of a trapezoid are 8 and 22 and the trapezoid's area is 135. Find the height

julia-pushkina [17]

Answer: 9

Step-by-step explanation:

A=(a+b)/2 *h

135= 30/2* h

135= 15 * h

135/15= h

9=h

8 0

3 years ago

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