Answer:
triangle MRP and triangle NPR looks like the right answer.
the selected option should be correct.
Vertex form is y = -(x+4)^2+9
Answer:
if you want to sketch the trapezoid you will also need other dimensions like height and the length of the parallel sides
Answer:
2(d-vt)=-at^2
a=2(d-vt)/t^2
at^2=2(d-vt)
Step-by-step explanation:
Arrange the equations in the correct sequence to rewrite the formula for displacement, d = vt—1/2at^2 to find a. In the formula, d is
displacement, v is final velocity, a is acceleration, and t is time.
Given the formula for calculating the displacement of a body as shown below;
d=vt - 1/2at^2
Where,
d = displacement
v = final velocity
a = acceleration
t = time
To make acceleration(a), the subject of the formula
Subtract vt from both sides of the equation
d=vt - 1/2at^2
d - vt=vt - vt - 1/2at^2
d - vt= -1/2at^2
2(d - vt) = -at^2
Divide both sides by t^2
2(d - vt) / t^2 = -at^2 / t^2
2(d - vt) / t^2 = -a
a= -2(d - vt) / t^2
a=2(vt - d) / t^2
2(vt-d)=at^2
Answer:
1) (x + 4)(x - ½) = 0
4x² + 16x = 0
2) 0.25x² + 0.8x - 8 = 0
3x² - 4x = 15
Step-by-step explanation:
1) (x + 4)(x - ½) = 0
x = -4, ½
4x² + 16x = 0
4x(x + 4) = 0
x = 0, -4
2) (x - 6)(x + 9) = 0
x = 6, -9
(x - 1)² = 4
(x - 1)² - (2)² = 0
(x - 1 - 2)(x - 1 + 2) = 0
(x - 3)(x + 1) = 0
x = 3, -1
These two are easier to solve using product = 0 property, while the other two would be easier using the quadratic formula
