The frictional force between the tires and the road prevent the car from skidding off the road due to centripetal force.
If the frictional force is less than the centripetal force, the car will skid when it navigates a circular path.
The diagram below shows that when the car travels at tangential velocity, v, on a circular path with radius, r, the centripetal acceleration of v²/ r acts toward the center of the circle.
The resultant centripetal force is (mv²)/r, which should be balanced by the frictional force of μmg, where μ = coefficient of kinetic friction., and mg is the normal reaction on a car with mass, m.
This principle is applied on racing tracks, where the road is inclined away from the circle to give the car an extra restoring force to overcome the centripetal force.
For this case we must simplify the following expression
We know that, by definition:
So, rewriting the expression we have:
We add similar terms taking into account that:
- Equal signs are added and the same sign is placed.
- Different signs are subtracted and the major's sign is placed:
Answer:
Answer:
B. Exponential.
Step-by-step explanation:
Each year you can find the estimated population for the following year by multiplying by 1 + 1.7% = 1.017.
The population estimate in x years time = 78,918 (1.017)^x.
Ax+by=c
y+4= -1/3(x-12)
remove ( )
y+4= -1/3x+4
subtract 4
y=-1/3x+0
add 1/3x
1/3x+y=0
hope this helps
the answers are the options
1.The rotation uses the rule (x, y)g(–x, –y).
<span> 4.The rotation is 180° about the origin.
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ooordinates blue triangle
A(1,1) B(1,3) and C(-5,3)
ooordinates red triangle
X(-1,-1) Y(-1,-3) and Z(5,-3)
let's check
coordinates blue triangle
A(1,1) B(1,3) and C(-5,3)
using the the rule ---- > (x, y)----------------- >g(–x, –y).
A(1,1)------------------ > A1(-1,-1)
B(1,3)------------------ > B1(-1,-3)
C(-5,3)------------------ >C1(5,-3)
therefore
∆A1B1C1=∆XYZ ------------------- > is ok