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3 years ago

Differentiate the following functions with respect to xx³ + 2x² - 5

Physics

2 answers:

sveticcg [70]3 years ago

6 0

Answer:

3x² + 10x

hope it's helpful

Norma-Jean [14]3 years ago

5 0

Answer:

d f(x) / dx = d (x^3 + 2 x^2 - 5) /dx = 3 x^2 + 4 x

(Use the rule for differentiation)

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Answer: The answer is B. Add more solute (took test)

Explanation:

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3 years ago

A middle-A tuning fork vibrates with a frequency f of 440 hertz (cycles per second). You strike a middle-A tuning fork with a fo

jeyben [28]

Answer:

P = 5sin(880πt)

Explanation:

We write the pressure in the form P = Asin2πft where A = amplitude of pressure, f = frequency of vibration and t = time.

Now, striking the middle-A tuning fork with a force that produces a maximum pressure of 5 pascals implies A = 5 Pa.

Also, the frequency of vibration is 440 hertz. So, f = 440Hz

Thus, P = Asin2πft

P = 5sin2π(440)t

P = 5sin(880πt)

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3 years ago

A driver in a 2000 kg Porsche wishes to pass to pass a slow-moving school bus on a four-lane road. What is the average power in

Kryger [21]

The average power is $3.0\cdot 10^6 W$

Explanation:

First of all, we calculate the work done to accelerate the car; according to the work-energy theorem, the work done is equal to the change in kinetic energy of the car:

$W=K_f -K_i= \frac{1}{2}mv^2-\frac{1}{2}mu^2$

where :

$K_f = \frac{1}{2}mv^2$ is the final kinetic energy of the car, with

m = 2000 kg is the mass of the car

v = 60 m/s is the final speed of the car

$K_i = \frac{1}{2}mu^2$ is the initial kinetic energy of the car, with

u = 30 m/s is initial speed of the car

Soolving:

$W=\frac{1}{2}(2000)(60)^2 - \frac{1}{2}(2000)(30)^2=2.7\cdot 10^6 J$

Now we can find the power required for the acceleration, which is given by

$P=\frac{W}{t}$

where

t = 9 s is the time elapsed

Solving:

$P=\frac{2.7\cdot 10^6}{9}=3.0\cdot 10^6 W$

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4 years ago

An asteroid is moving along a straight line. A force acts along the displacement of the asteroid and slows it down. The asteroid

Setler79 [48]

Answer:

$- 7.04\times10^{11} J$

$5.03\times10^{5} N$

Explanation:

$m$ = mass of the asteroid = 43000 kg

$v_{o}$ = initial speed of asteroid = 7600 m/s

$v$ = final speed of asteroid = 5000 m/s

$W$ = Work done by the force on asteroid

Using work-change in kinetic energy theorem

$W = (0.5) m (v^{2} - v_{o}^{2})\\W = (0.5) (43000) (5000^{2} - 7600^{2})\\W = - 7.04\times10^{11} J$

$F$ = magnitude of force on asteroid

$d$ = distance traveled by asteroid while it slows down = 1.4 x 10⁶ m

Work done by the force on the asteroid to slow it down is given as

$W = - F d\\- 7.04\times10^{11} = - F (1.4\times10^{6})\\F = 5.03\times10^{5} N$

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3 years ago

Why are solids good at transferring heat through conduction?

seraphim [82]

The chemical bonds alow it to pass to the other object.

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4 years ago

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Differentiate the following functions with respect to xx³ + 2x² - 5​

Differentiate the following functions with respect to xx³ + 2x² - 5