Momentum = mass x velocity
Before collision
Momentum 1 = 2 kg x 20 m /s = 40 kg x m/s
Momentum 2 = 3 kg x -10m/s = -30 kg x m/s
After collision
Momentum 1 = 2 kg x -5 m/s = -10 m/s
Momentum 2 = 3 kg x V2 = 3V2
Total momentum before = total momentum after
40 + -30 = -10 + 3V2
V2 = <span>6.67 m/s
Total kinetic energy before
</span><span>= (1/2) [ 2 kg * 20 m/s * 2 + 3 kg * ( -10 m/s) *2 ]
= 550 J
</span>
<span>Total kinetic energy after
</span>= (1/2) [ 2 kg * ( - 5 m/s) * 2 + 3 kg * 6.67 m/s *2 ]
= 91.73 J
Total kinetic energy lost during collision
=<span>550 J - 91.73 J
= 458.27 J</span>
Answer:
momentum=mass×velocity
momentum =400kg×20m/s=8000kg.m/s
From the calculations, the final momentum of B is 8.16 m/s
<h3>What is conservation of linear momentum?</h3>
According to the principle of the conservation of linear momentum, the momentum before collision is equal to the total momentum after collision.
This implies that;
MaUa + MbUb = MaVa + MaVa
Substituting values;
(0.08 kg * 0.5 m/s) + (0.05 kg * 0 m/s) = (0.08 kg * −0.1 m/s) + (0.05 kg * v)
0.4 = -0.008 + 0.05v
v = 8.16 m/s
Learn more about more about momentum: brainly.com/question/24030570:
#SPJ1
To calculate the horizontal distance traveled by the ball, we first calculate the total time it takes to reach the ground as follows:
t = √[2y/g] = <span>√[2(0.55) / 9.81]
t = 0.33 s
The horizontal distance would be
</span><span>X = Vx*t = 1.2*√[2*.55/9.8] = 0.4 m
</span>
Hope this helps.
Answer:
a
Explanation:
<em>a_c</em><em> </em><em>=</em><em> </em><em>v</em><em>_t</em><em>^</em><em>2</em><em>/</em><em>r</em>
<em>a_c</em><em> </em><em>=</em><em> </em>(0.5)^2/0.03
<em>a_c</em><em> </em><em>=</em><em> </em>8.33 m/s^2
