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Minchanka [31]
3 years ago
5

Noah stands 170 meters away from a steep canyon wall. He shouts and hears the echo of his

Physics
1 answer:
bezimeni [28]3 years ago
6 0
340 ms


I got it right and I hope you do as well
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A 2000-kg car moving with a speed of 20 m/s collides with and sticks to a 1500-kg car at rest at a stop sign. Show that because
amid [387]

Answer:

13.33m/s

Explanation:

Given data

m1= 2000kg

u1= 20m/s

m2= 1500kg

u2= 0m/s

v1= 10m/s

Required

The speed of the sticks

We know that  from the expression for the conservation of momentum

m1u1+m2u2= m1v1+m2v2

2000*20+1500*0=2000*10+1500*v2

40000=20000+1500v2

collect like terms

40000-20000= 1500v2

20000= 1500v2

v2= 20000/1500

v2= 13.33 m/s

Hence the velocity of the sticks is 13.33m/s

8 0
3 years ago
A smoke detector is an electronic fire-protection device that automatically senses the presence of smoke as a key indicator of f
Colt1911 [192]

Answer:

Photoelectric-type alarms aim a light source into a sensing chamber at an angle away from the sensor. Smoke enters the chamber, reflecting light onto the light sensor; triggering the alarm.

Explanation:

nfpa.org is the website with theanswer

7 0
2 years ago
When air pressure decreases, the mercury in a barometer _____.
siniylev [52]

Answer:

The mercury in the barometer will go down as there is less air pressing down on the bulb of the barometer to push mercury up.

Explanation:

7 0
3 years ago
PLEASE HELP!!!!
Sidana [21]

Answer:

B )-14000N

Explanation:

F=mv-mu

t

F =<u>2</u><u>5</u><u>5</u><u>0</u><u>(</u><u>0</u><u>)</u><u>-</u><u>2</u><u>5</u><u>5</u><u>0</u><u>(</u><u>6</u><u>)</u>

1.1

F = -13909.09

approximately -14000N

4 0
3 years ago
A 45-kg box containing a new bicycle has just arrived in the front porch and two brothers are fighting over it. The first brothe
Hitman42 [59]

Answer:

0.17

Explanation:

Draw a free body diagram.  There are five forces on the box:

Weight force mg pulling down

Normal force Fn pushing up

Applied force 52 N pulling to the left

Applied force 125 N pulling to the right

Friction force Fnμ pulling to the left

Sum of the forces in the y direction:

∑F = ma

Fn − mg = 0

Fn = mg

Fn = (45)(9.8)

Fn = 441

Sum of the forces in the x direction:

∑F = ma

125 − 52 − Fnμ = 0

Fnμ = 73

μ = 73 / Fn

μ = 73 / 441

μ = 0.17

7 0
3 years ago
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