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Zepler [3.9K]
2 years ago
5

S ={x|x are numbers completely divisible by 5 and x<100}

Mathematics
1 answer:
Liula [17]2 years ago
7 0

Answer:

Step-by-step explanation:3

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A cylinder and a cone have the same measurements for height and radius. The cylinder has a volume of 45 cm ^ 3 . What is the vol
sweet [91]

Answer:

91,125

Step-by-step explanation:

4 0
2 years ago
Suppose the graph of a cubic polynomial function has the same zeroes and passes through the coordinate (0, –5). Describe the ste
olga_2 [115]
1. "the graph has the same zeros" : so let a be the "triple" root of the cubic polynomial function.

2. So f(x)=(x-a)^{3}

3. Don't forget that the expression might have a coefficient b as well, and still maintain the conditions: 
 
f(x)=b(x-a)^{3}

4. Now, f(0)=-5 so  -5=f(0)=b(0-a)^{3}=b(-a) ^{3}=-ba ^{3}

-5=-ba ^{3}

5=ba ^{3}

b= \frac{5}{ a^{3} }

5. the function is f(x)=\frac{5}{ a^{3} }(x-a)^{3} where a can be any real number except 0
7 0
3 years ago
Read 2 more answers
Please help me literally need this to be answered in 2 hours P-L-E-A-S-E !!
Sonja [21]

Answer:

Yeah with that type of problem

Step-by-step explanation:

You aint getting answered for the next 4 hours <3

6 0
2 years ago
Find the distance between each pair of points
dolphi86 [110]

Answer: the correct answer is 20

Step-by-step explanation:

The formula for determining the distance between two points on a straight line is expressed as

Distance = √(x2 - x1)² + (y2 - y1)²

Where

x2 represents final value of x on the horizontal axis

x1 represents initial value of x on the horizontal axis.

y2 represents final value of y on the vertical axis.

y1 represents initial value of y on the vertical axis.

From the graph given,

x2 = - 7

x1 = 5

y2 = - 7

y1 = 9

Therefore,

Distance = √(- 7 - 5)² + (- 7 - 9)²

Distance = √(- 12²) + (- 16)²

= √(144 + 256) = √400

Distance = 20

5 0
3 years ago
Let f(x)=x^3-x-1
alexira [117]
f(x) = x^3 - x - 1

To find the gradient of the tangent, we must first differentiate the function.

f'(x) = \frac{d}{dx}(x^3 - x - 1) = 3x^2 - 1

The gradient at x = 0 is given by evaluating f'(0).

f'(0) = 3(0)^2 - 1 = -1

The derivative of the function at this point is negative, which tells us <em>the function is decreasing at that point</em>.

The tangent to the line is a straight line, so we will have a linear equation of the form y = mx + c. We know the gradient, m, is equal to -1, so

y = -x + c

Now we need to substitute a point on the tangent into this equation to find c. We know a point when x = 0 lies on here. To find the y-coordinate of this point we need to evaluate f(0).

f(0) = (0)^3 - (0) - 1 = -1

So the point (0, -1) lies on the tangent. Substituting into the tangent equation:

y = -x + c \\\\ -1 = -(0) + c \\\\ -1 = c \\\\ \text{Equation of tangent is } \boxed{y = -x - 1}
6 0
3 years ago
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