1. "the graph has the same zeros" : so let a be the "triple" root of the cubic polynomial function.
2. So f(x)=

3. Don't forget that the expression might have a coefficient b as well, and still maintain the conditions:

4. Now, f(0)=-5 so




5. the function is

where a can be any real number except 0
Answer:
Yeah with that type of problem
Step-by-step explanation:
You aint getting answered for the next 4 hours <3
Answer: the correct answer is 20
Step-by-step explanation:
The formula for determining the distance between two points on a straight line is expressed as
Distance = √(x2 - x1)² + (y2 - y1)²
Where
x2 represents final value of x on the horizontal axis
x1 represents initial value of x on the horizontal axis.
y2 represents final value of y on the vertical axis.
y1 represents initial value of y on the vertical axis.
From the graph given,
x2 = - 7
x1 = 5
y2 = - 7
y1 = 9
Therefore,
Distance = √(- 7 - 5)² + (- 7 - 9)²
Distance = √(- 12²) + (- 16)²
= √(144 + 256) = √400
Distance = 20

To find the gradient of the tangent, we must first differentiate the function.

The gradient at x = 0 is given by evaluating f'(0).

The derivative of the function at this point is negative, which tells us <em>the function is decreasing at that point</em>.
The tangent to the line is a straight line, so we will have a linear equation of the form y = mx + c. We know the gradient, m, is equal to -1, so

Now we need to substitute a point on the tangent into this equation to find c. We know a point when x = 0 lies on here. To find the y-coordinate of this point we need to evaluate f(0).

So the point (0, -1) lies on the tangent. Substituting into the tangent equation: