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2 years ago

Write 3 _ 6 in lowest terms.

Mathematics

2 answers:

lbvjy [14]2 years ago

8 0

1/2 is the correct answer, hope this helps

Pepsi [2]2 years ago

4 0

Answer:

1/2

Step-by-step explanation:

3 is half of 6 so the smallest term would be 1/2.

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The bases on a softball field are square. What is the area of each base if one side is 15 inches? Do not write units.

iogann1982 [59]

Area of a square is side length^2

Area = 15^ 2 = 15 x 15 = 225 square inches.

4 0

2 years ago

Read 2 more answers

25-42 Differentiate the function. 25. <img src="https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B5%7D%2B5%5E%7Bx%7D" id="TexFormula

natulia [17]

Answer:

y'= 5x^4 + 5^x In(5)

Step-by-step explanation:

Differentiate with Respect to x

f(x)'=5x^4 + In(5^x)

f(x)'= 5x^4 + x In(5)

with respect to x, we have

y'= 5x^4 + y In(5)

y'= 5x^4 + 5^x In(5)

8 0

2 years ago

The base of a solid in the first quadrant of the xy plane is a right triangle bounded by the coordinate axes and the line x + y

Ivahew [28]

The area of an equilateral triangle of side "s" is s^2*sqrt(3)/4. So the volume of the slices in your problem is

(x - x^2)^2 * sqrt(3)/4.

Integrating from x = 0 to x = 1, we have

[(1/3)x^3 - (1/2)x^4 + (1/5)x^5]*sqrt(3)/4

= (1/30)*sqrt(3)/4 = sqrt(3)/120 = about 0.0144.

Since this seems quite small, it makes sense to ask what the base area might be...integral from 0 to 1 of (x - x^2) dx = (1/2) - (1/3) = 1/6. Yes, OK, the max height of the triangles occurs where x - x^2 = 1/4, and most of the triangles are quite a bit shorter...

8 0

3 years ago

Show tan(???? − ????) = tan(????)−tan(????) / 1+tan(????) tan(????) .

anyanavicka [17]

Answer:

See the proof below

Step-by-step explanation:

For this case we need to proof the following identity:

$tan(x-y) = \frac{tan(x) -tan(y)}{1+ tan(x) tan(y)}$

We need to begin with the definition of tangent:

$tan (x) =\frac{sin(x)}{cos(x)}$

So we can replace into our formula and we got:

$tan(x-y) = \frac{sin(x-y)}{cos(x-y)}$ (1)

We have the following identities useful for this case:

$sin(a-b) = sin(a) cos(b) - sin(b) cos(a)$

$cos(a-b) = cos(a) cos(b) + sin (a) sin(b)$

If we apply the identities into our equation (1) we got:

$tan(x-y) = \frac{sin(x) cos(y) - sin(y) cos(x)}{sin(x) sin(y) + cos(x) cos(y)}$ (2)

Now we can divide the numerator and denominato from expression (2) by $\frac{1}{cos(x) cos(y)}$ and we got this:

$tan(x-y) = \frac{\frac{sin(x) cos(y)}{cos(x) cos(y)} - \frac{sin(y) cos(x)}{cos(x) cos(y)}}{\frac{sin(x) sin(y)}{cos(x) cos(y)} +\frac{cos(x) cos(y)}{cos(x) cos(y)}}$

And simplifying we got:

$tan(x-y) = \frac{tan(x) -tan(y)}{1+ tan(x) tan(y)}$

And this identity is satisfied for all:

$(x-y) \neq \frac{\pi}{2} +n\pi$

8 0

2 years ago

Building and reduce 1/2 = / 10

Vladimir [108]

Answer: 5/10

Explanation: Compare the denominators. Since 2 ⋅ 5 = 10, multiply the numerator 1 by 5 to get 5.

7 0

2 years ago