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3 years ago

Solve for x. x = 6° x = 15° x = 30° x = 90°

Mathematics

1 answer:

Akimi4 [234]3 years ago

6 0

Step-by-step explanation:

Your question isn't complete.

But if you are asking for finding the value of variable then, you should follow these things

Use BODMAS if necessary
For cancelling a positive number you should subtract it from both sides

x+2=6

x+2-2=6-2

x=4

Hence, positive number is cancelled

For cancelling negative numbers add it both sides

x-3=1

x-3+3=1+3

x=1

Hence, negative number is cancelled

For cancelling a number in product form number divide both sides by same number

3x=6

3x/3=6/3

x=2

Hence, the number in product form is cancelled

For cancelling the number in divide form, multiply both sides by the same number

y÷3=1

y÷3×3=1×3

y=3

Hence, the number in divide form is cancelled

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Answer:

Step-by-step explanation:

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3 years ago

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Answer:

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3 years ago

Help with Algebra 2: 1. <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B7%5D%7Bx%5E5%7D%20%7D%7B%5Csqrt%5B4%5D%7Bx%5E2%7D%

Mars2501 [29]

Answer:

See explanation

Step-by-step explanation:

1. Given the expression

$\dfrac{\sqrt[7]{x^5} }{\sqrt[4]{x^2} }$

Note that

$\sqrt[7]{x^5}=x^{\frac{5}{7}} \\ \\\sqrt[4]{x^2}=x^{\frac{2}{4}}=x^{\frac{1}{2}}$

When dividing $\sqrt[7]{x^5}$ by $\sqrt[4]{x^2},$ we have to subtract powers (we cannot subtract 4 from 7, because then we get another expression), so

$\dfrac{5}{7}-\dfrac{2}{4}=\dfrac{5}{7}-\dfrac{1}{2}=\dfrac{5\cdot 2-1\cdot 7}{14}=\dfrac{3}{14}$

and the result is $x^{\frac{3}{14}}=\sqrt[14]{x^3}$

2. Given equation $3\sqrt[4]{(x-2)^3} -4=20$

Add 4:

$3\sqrt[4]{(x-2)^3} -4+4=20+4\\ \\3\sqrt[4]{(x-2)^3}=24$

Divide by 3:

$\sqrt[4]{(x-2)^3} =8$

Rewrite the equation as:

$(x-2)^{\frac{3}{4}}=8\\ \\(x-2)^{\frac{3}{4}}=2^3$

Hence,

$\left((x-2)^{\frac{3}{4}}\right)^{\frac{4}{3}}=(2^3)^{\frac{4}{3}}\\ \\x-2=2^{3\cdot \frac{4}{3}}\\ \\x-2=2^4\\ \\x-2=16\\ \\x-2+2=16+2\\ \\x=18$

3 0

3 years ago

Jay simplified the expression -3 × (3 + 12 ÷ 3) - 4. For his first step, he added 3 + 12 to get 15. What was Jay’s error?

ale4655 [162]

Answer:

He should have divided 12 ÷ 3 first.

Step-by-step explanation:

Following PEMDAS/BODMAS, the first step is solving equations in parentheses. Since the parentheses contain a multi-step equation, Jay needs to follow PEMDAS for inside the parentheses as well. Instead of adding 3+12 first, he should have done division first (12 ÷ 3).

How the problem should be solved:

-3 × (3 + 12 ÷ 3) - 4

-3 × (3 + 4) -4

-3 × 7 - 4

-21 - 4

-25

3 0

3 years ago

Read 2 more answers

An equation is shown.<br> 3x + 4/5 = 7 – 2x<br> What is the solution to the equation?<br> x=

just olya [345]

Answer:

Step-by-step explanation:

3x + 4/5 = 7 – 2x

Multiply each term by 5

15x + 4 = 35 -10x

15x + 10x = 35 - 4

25x = 31

x = 31/25

x = 1 6/25

4 0

3 years ago

Read 2 more answers