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2 years ago

Geometry question don’t understand 1 and 3

Mathematics

1 answer:

nasty-shy [4]2 years ago

7 0

Need help myself not sure sorry

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Please help asap! Add using the number line.

sweet-ann [11.9K]

Answer:

0.6

Step-by-step explanation:

1) 1.4-0.8 (A negative and a positive equals a negative, then you just subtract. On the number line you would start at 1.4 and go back)

hope this helps!

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3 years ago

Kim is planning a trip to Spain. She will stay there for a total of thirteen nights. She has found two options for her lodging:

lys-0071 [83]

Answer:

Step-by-step explanation:

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3 years ago

HELP ASAP PLS AND THANKS!!!!

likoan [24]

The first one is the correct answer

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3 years ago

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1.) A florist sells bouquets for $12.25 each. Amiyah

deff fn [24]

Answer:

Step-by-step explanation:

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3 years ago

Choose one of the factors of 500x3 + 108y18

sammy [17]

Answer:

Option C

Therefore, one of the factors of $500x^3 +108y^\left (18\right )$ is $(5x+3y^6)$ .

Step-by-step explanation:

Given: $500x^3 +108y^\left (18\right )$

the common factor from $500x^3$ and $108y^\left (18\right )$ is 4.

therefore, $4\cdot \left ( 125x^3+27y^\left (18\right ) \right )$

$4\cdot \left ( (5x)^3+(3y^6)^3 \right))$

Now, use the formula for above expression: $(a^3+b^3)=(a+b)(a^2-ab+b^2)$

here, $a=5x$ and $b=3y^6$

$( (5x)^3+(3y^6)^3 \right))$ $=(5x+3y^6)(25x^2-15xy^6+9y^12)$

Therefore, we have

$500x^3 +108y^\left (18\right )$ $=4\cdot (5x+3y^6)\left (25x^2-15xy^6+9y^\left ( 12 \right ) \right )$

Therefore, one of the factors of $500x^3 +108y^\left (18\right )$ is $(5x+3y^6)$ .

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3 years ago

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