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Ghella [55]
3 years ago
13

8(5x+ 2) = 296 how to solve this

Mathematics
2 answers:
Katarina [22]3 years ago
8 0

Answer:

x = 7

Step-by-step explanation:

8(5x + 2) = 296

40x + 16 = 296

40x = 280

x = 7

deff fn [24]3 years ago
6 0

Answer:

x=7

Step-by-step explanation:

➼Okay, so first thing you need to do is to distribute the 8 to everything in the parentheses:

8(5x+ 2) = 296

8 times 5x

8 times 2

(8 x 5x) + (8 x 2) = 40x + 16

➼Now you solve for x

40x+16=296

➼to get rid of 40 you have to do the opposite and divide it by everything

40x+16=296

40/40=0

16/40=0.4

296/40=7.4

➼all adds up to x + .4 = 7.4 but to get the x alone you need to get rid of the .4, we'll do this by doing the opposite and subtract it from everything

.4-.4=0

7.4-.4=7

➼so in conclusion

x=7

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Answer:

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Step-by-step explanation:

Length of the wire = 28 ft has been cut in two pieces.

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Let the length of the wire which forms the square is 'l' ft.

Area of the square = (side)²

Perimeter of the square = 4(side) = l

Length of one side = \frac{l}{4}

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Area of the circle formed = πr²

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= \frac{(28-l)^{2}}{4\pi }

Combined area of the square and circle

= \frac{l^{2}}{16} + \frac{(28-l)^{2}}{4\pi }

= \frac{l^{2}}{16} + \frac{(28-l)^{2}}{4\pi }

Now to maximize the area we will find the derivative of the area with respect to l.

\frac{dA}{dl}=\frac{d}{dl}[\frac{l^{2}}{16}+\frac{(28-l)^{2}}{4\pi}]

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= \frac{2l}{16}+\frac{(2l-56)}{4\pi }

Now equate the derivative to zero.

\frac{2l}{16}+\frac{(2l-56)}{4\pi } = 0

(2l-56)=-\frac{2l}{16}\times 4\pi

(2l-56)=-\frac{\pi l}{2}

2l+\frac{\pi l}{2}=56

\frac{(4l+l\pi )}{2}=56

l(4 + π) = 112

l(4 + 3.14) = 112

l = \frac{112}{7.14}

l = 15.69 ft

Length of the other part = 28 - 15.69 = 12.31 ft

Therefore, wire should be cut in two parts with the length = 15.69 ft and 12.31 ft

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