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Schach [20]
3 years ago
8

Which angles are congruent to each other?

Mathematics
2 answers:
igomit [66]3 years ago
7 0

angles dea and bec

this is right

serg [7]3 years ago
3 0

Answer:

∠DEA and ∠BEC

Step-by-step explanation:

Because they are vertical angles

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Sergio makes belts in his garage.He makes a certain number of belts for every hour he works.what is the missing value in the tab
aleksklad [387]
Is 12 Because the pattern is 2+1=3; 4+2=6;
6+3=9; 8+4=12 and 10+5=15
8 0
3 years ago
A box that measures 15 inches by 5 inches by 3 inches.
tino4ka555 [31]

Answer: cubic inches.

Step-by-step explanation: When calculating volume, all of the units must be cubed. And all of the measurements are in inches.

6 0
3 years ago
Read 2 more answers
For integers a, b, and c, consider the linear Diophantine equation ax C by D c: Suppose integers x0 and y0 satisfy the equation;
Dmitrij [34]

Answer:

a.

x = x_1+r(\frac{b}{gcd(a, b)} )\\y=y_1-r(\frac{a}{gcd(a, b)} )

b. x = -8 and y = 4

Step-by-step explanation:

This question is incomplete. I will type the complete question below before giving my solution.

For integers a, b, c, consider the linear Diophantine equation

ax+by=c

Suppose integers x0 and yo satisfy the equation; that is,

ax_0+by_0 = c

what other values

x = x_0+h and y=y_0+k

also satisfy ax + by = c? Formulate a conjecture that answers this question.

Devise some numerical examples to ground your exploration. For example, 6(-3) + 15*2 = 12.

Can you find other integers x and y such that 6x + 15y = 12?

How many other pairs of integers x and y can you find ?

Can you find infinitely many other solutions?

From the Extended Euclidean Algorithm, given any integers a and b, integers s and t can be found such that

as+bt=gcd(a,b)

the numbers s and t are not unique, but you only need one pair. Once s and t are found, since we are assuming that gcd(a,b) divides c, there exists an integer k such that gcd(a,b)k = c.

Multiplying as + bt = gcd(a,b) through by k you get

a(sk) + b(tk) = gcd(a,b)k = c

So this gives one solution, with x = sk and y = tk.

Now assuming that ax1 + by1 = c is a solution, and ax + by = c is some other solution. Taking the difference between the two, we get

a(x_1-x) + b(y_1-y)=0

Therefore,

a(x_1-x) = b(y-y_1)

This means that a divides b(y−y1), and therefore a/gcd(a,b) divides y−y1. Hence,

y = y_1+r(\frac{a}{gcd(a, b)})  for some integer r. Substituting into the equation

a(x_1-x)=rb(\frac{a}{gcd(a, b)} )\\gcd(a, b)*a(x_1-x)=rba

or

x = x_1-r(\frac{b}{gcd(a, b)} )

Thus if ax1 + by1 = c is any solution, then all solutions are of the form

x = x_1+r(\frac{b}{gcd(a, b)} )\\y=y_1-r(\frac{a}{gcd(a, b)} )

In order to find all integer solutions to 6x + 15y = 12

we first use the Euclidean algorithm to find gcd(15,6); the parenthetical equation is how we will use this equality after we complete the computation.

15 = 6*2+3\\6=3*2+0

Therefore gcd(6,15) = 3. Since 3|12, the equation has integral solutions.

We then find a way of representing 3 as a linear combination of 6 and 15, using the Euclidean algorithm computation and the equalities, we have,

3 = 15-6*2

Because 4 multiplies 3 to give 12, we multiply by 4

12 = 15*4-6*8

So one solution is

x=-8 & y = 4

All other solutions will have the form

x=-8+\frac{15r}{3} = -8+5r\\y=4-\frac{6r}{3} =4-2r

where r ∈ Ζ

Hence by putting r values, we get many (x, y)

3 0
3 years ago
Fill in the blanks in the following proof.
NARA [144]

Answer:

Table :

     Statements                 Reasons

1)ΔEGC≅ΔEGB                 Given

2)EB = EC                          Corresponding Parts of Congruent

                                          Triangles are Congruent

3) BC = BE                         Given

4) By 2 and 3                      EB≅EC≅BC

5)∠BEC = 60°                     ΔBEC is an equilateral triangle

Step-by-step explanation:

We are given that BE = BC  ---1

We are also given that ΔEGC≅ΔEGB

So, BE = CE(Corresponding Parts of Congruent Triangles are Congruent) ---2

Now By 1 and 2

BE=BC=CE

In ΔBEC

BE=BC=CE

Since all sides are equal . So, it is an equilateral triangle

All angles of equilateral triangle are also equal i.e. 60°

So, ∠BEC = 60°

Hence proved

Table :

     Statements                 Reasons

1)ΔEGC≅ΔEGB                 Given

2)EB = EC                          Corresponding Parts of Congruent

                                          Triangles are Congruent

3) BC = BE                         Given

4) By 2 and 3                      EB≅EC≅BC

5)∠BEC = 60°                     ΔBEC is an equilateral triangle

7 0
3 years ago
What is the answer for 3r=10+5 when r=10
katen-ka-za [31]

Answer:

Step-by-step explanation:

What is the VALUE OF 3r=10+5 when r=10?

substitute 10 for r in 3r=10+5.  We get:

3(10) = 10 + 5, or 30 = 15.  This equation is FALSE when r = 10.

You could solve the equation for r, however:

3r=10+5 becomes 3r = 15, and so r = 5.  5 is a solution; 10 is not a solution.

6 0
3 years ago
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