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andrew11 [14]
3 years ago
13

Test IV

Mathematics
1 answer:
Elan Coil [88]3 years ago
3 0

Answer:

I think the image above will help you

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(Algebra2 HELP please)
Savatey [412]

Maximizing profit, is a way of getting the highest possible profit, from a function.

The bakery should make 45 loaves of A and 0 loaves of B, to maximize profit

To do this, we make use of the following representations.

x represents source A, and y represents source B

So, we have:

<u>Constraint 1: </u>

A uses 5 pounds, and B uses 2 pounds of oats.

Available: 180

The above condition is represented as;

\mathbf{5x + 2y \le 180}

<u>Constraint 2: </u>

A and B use 3 pounds of flour each.

Available: 135

The above condition is represented as;

\mathbf{3x + 3y \le 135}

<u>Objective function</u>

A yields $40, while B yields $30

So, the objective function is:

\mathbf{Maximize\ Z = 40x + 30y}

So, we have:

\mathbf{Maximize\ Z = 40x + 30y}

Subject to

\mathbf{5x + 2y \le 180}

\mathbf{3x + 3y \le 135}

\mathbf{x,y \ge 0}

See attachment for the graph of the subjects

From the graph, we have the corner points to be:

\mathbf{(x,y) = \{(0,45),(30,15),(45,0)\}}

Substitute these values in the objective function

\mathbf{Z = 40(0) +30(45) = 1350}

\mathbf{Z = 40(30) +30(15) = 1650}

\mathbf{Z = 40(45) +30(0) = 1800}

The maximum value of Z is at: (45,0)

This means that: the bakery should make 45 loaves of A and 0 loaves of B, to maximize profit

Read more about maximizing functions at:

brainly.com/question/14728529

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Please help me ASAP answer both questions
NNADVOKAT [17]

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b and c

Step-by-step explanation:

i did it

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