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scZoUnD [109]
3 years ago
11

Write this expression in its most simplified, factored form. 12x2y − 32xy + 8y

Chemistry
2 answers:
pantera1 [17]3 years ago
8 0

Answer:

12x {}^{2} y - 32xy + 8y

first factorise out 4y :

= 4y( {3x}^{2}  - 8x + 2)

zzz [600]3 years ago
6 0

Answer:

That dude above is right

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Under which conditions of temperature and pressure does a real gas behave most like an ideal gas
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The specific heat of palladium is 0.239 J/g°C. How much heat (q) is released when a 10.0 g piece of platinum cools from 100.0°C
Andrej [43]

Answer:

119.5 J

Explanation:

First we <u>calculate the temperature difference</u>:

  • ΔT = 100 °C - 50 °C = 50 °C

Then we can <u>calculate the heat released</u> by using the following formula:

  • q = Cp * ΔT * m

Where q is the heat, Cp is the specific heat, ΔT is the temperature difference and m is the mass.

We <u>input the data</u>:

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Calculate the number of molecules and atoms present in 124 g of phosphorus
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How would you prepare 2.00 l of a 0.25 m acetate buffer at ph= 4.50 from concentrated acetic acid (17.4 m) and 1.00 m naoh? the
zvonat [6]

The reaction of acetic acid with sodium hydroxide is:

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The ratio of A-/HA is calculated as follows:

According to Henderson Hasslebach equation:


[A-]/[HA] = 10^p^H^-^p^K^_a

= 10^4^.^7^6^-^4^.^5^ = ^2^.^1^8

The total concentration of HA and A- = 2.0 L * 0.25 M = 0.5 mol.

[ A- ]+ [ HA ]= 0.5

[ A^- ] = 0.5 – [ HA]

[ HA] = 0.156 mol and [ A- ]= 0.343 mol

Total of 0.5 moles of acetic acid is required:

0.5 mol HA * 60.0 g

HA = 30.0 g acetic acid

Conversion of 0.343 moles of the acetic acid to acetate can be performed by adding NaOH

0.343 mol HA * (1 mol NaOH/1 mol HA) * (1000 mL/1 mol NaOH)

= 343 mL  

Thus, 343 mL of 1M NaOH is required

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3 years ago
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