At higher temperature, and lower pressure.
Answer:
119.5 J
Explanation:
First we <u>calculate the temperature difference</u>:
- ΔT = 100 °C - 50 °C = 50 °C
Then we can <u>calculate the heat released</u> by using the following formula:
Where q is the heat, Cp is the specific heat, ΔT is the temperature difference and m is the mass.
We <u>input the data</u>:
- q = 0.239 J/g°C * 50 °C * 10.0 g
The correct answer is A.
Gravitational force will attract any object with mass. It's why you're not floating in the air right now, but rather making contact with the ground. At the same time, since you have mass, you're also attracting other objects right now with gravitational force.
6.022*10^23 molecules
4*6.022*10^23 atoms = 24.08*10^23 atoms
The reaction of acetic acid with sodium hydroxide is:

The ratio of A-/HA is calculated as follows:
According to Henderson Hasslebach equation:
![[A-]/[HA] = 10^p^H^-^p^K^_a](https://tex.z-dn.net/?f=%5BA-%5D%2F%5BHA%5D%20%3D%2010%5Ep%5EH%5E-%5Ep%5EK%5E_a)

The total concentration of HA and A- = 2.0 L * 0.25 M = 0.5 mol.
![[ A- ]+ [ HA ]= 0.5](https://tex.z-dn.net/?f=%5B%20A-%20%5D%2B%20%5B%20HA%20%5D%3D%200.5)
![[ A^- ] = 0.5 – [ HA]](https://tex.z-dn.net/?f=%5B%20A%5E-%20%5D%20%3D%200.5%20%E2%80%93%20%5B%20HA%5D)
[ HA] = 0.156 mol and [ A- ]= 0.343 mol
Total of 0.5 moles of acetic acid is required:

HA = 30.0 g acetic acid
Conversion of 0.343 moles of the acetic acid to acetate can be performed by adding NaOH

= 343 mL
Thus, 343 mL of 1M NaOH is required