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Leni [432]
3 years ago
7

Click the "draw structure" button to launch the drawing utility. Draw the product formed when 2−heptanone (CH3COCH2CH2CH2CH2CH3)

is treated with (CH3)2CHNH2 in the presence of mild acid. 2−Heptanone is partly responsible for the odor of bleu cheese.

Chemistry
1 answer:
lys-0071 [83]3 years ago
4 0

Answer:

Structure of the product has been shown below.

Explanation:

This is an example of condensation reaction between a primary amine and a ketone. Here an imine is formed.

In the first step, protonation of cabonyl oxygen occurs. In the 2nd step, amine gives a nucleophilic addition reaction at carbon center of protonated carbonyl group. In the 3rd step, proton transfer takes place. In the 4th step, dehydration occurs. Lastly, deprotonation leads to formation of an imine.

Full mechanism has been shown below.

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An endothermic process is one in which heat is ________ from the surroundings. (2 points)
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7 0
3 years ago
An excess of oxygen reacts with 451.4 g of lead, forming 374.7 g of lead(II) oxide. Calculate the percent yield of the reaction.
Stels [109]

Answer: The percent yield of the reaction is 77.0 %

Explanation:

2Pb+O_2\rightarrow 2PbO

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

\text{Number of moles of lead}=\frac{451.4g}{207.2g/mol}=2.18moles

\text{Number of moles of lead oxide}=\frac{374.7g}{223.2g/mol}=1.68moles

According to stoichiometry:

2 moles of Pb produces = 2 moles of PbO_2

2.18 moles of Pb is produced by=\frac{2}{2}\times 2.18=2.18moles of PbO_2

Mass of PbO_2 =moles\times {\text {Molar mass}}=2.18\times 223.2g/mol=486.6

percent yield =\frac{374.7g}{486.6g}\times 100=77.0\%

3 0
3 years ago
Is the atom indicated with an arrow nucleophilic, electrophilic, acidic, more than one of these choices, or none of these choice
9966 [12]

Answer:

Acidic

Explanation:

Please kindly check attachment for the detailed step by step solution of the given problem.

7 0
3 years ago
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