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Elza [17]
3 years ago
10

A pair of equations is shown below:

Mathematics
1 answer:
Margarita [4]3 years ago
4 0

<em><u>your </u></em><em><u>question</u></em><em><u>:</u></em><em><u> </u></em>

A pair of equations is shown below:

y = 7x − 9

y = 3x − 1

Part A: In your own words, explain how you can solve the pair of equations graphically. Write the slope and y-intercept for each equation that you will plot on the graph to solve the equations. (6 points) YOU HAVE ALREADY ANSWERED

Part B: What is the solution to the pair of equations? (4 points)

<em><u>answer:</u></em><em><u> </u></em>

<em>t</em><em>he </em><em>solution </em><em>to </em><em>the </em><em>pair </em><em>of </em><em>equations </em><em>would </em><em>be </em>

(2,5)

<em><u>how </u></em><em><u>do </u></em><em><u>we </u></em><em><u>get </u></em><em><u>this</u></em><em><u>?</u></em>

<em> </em><em>you </em><em>put </em><em>both </em><em>equations </em><em>in </em><em>a </em><em>desmos </em><em>graphing </em><em>calculator</em><em> </em>

<em>hope </em><em>this </em><em>helps,</em><em> </em><em>have </em><em>a </em><em>great </em><em>night </em><em>:</em><em>)</em><em> </em>

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Suppose that 10% of all homeowners in an earthquake-prone area of California are insured against earthquake damage. Four homeown
guapka [62]

Remainder of question:

Find the probability distribution of x

Answer:

The random variable x is defined as: X = {0, 1, 2, 3, 4}

The probability distribution of X:

P(X = 0) = 0.656

P(X = 1) = 0.2916

P(X= 2) = 0.0486

P(X=3) = 0.0036

P(X = 4) = 0.0001

Step-by-step explanation:

Sample size, n = 4

Random variable, X = {0, 1, 2, 3, 4}

10% (0.1) of the homeowners are insured against earthquake, p = 0.1

Proportion of homeowners who are not insured against earthquake, q = 1 - 0.1

q = 0.9

Probability distribution of x,

P(X = r) = ^nC_r *p^r q^{n-r} \\\\P(X= 0) =(^4C_0 *p^1 q^4 )\\P(X=0) = (^4C_0 *0.1^0 0.9^4 ) = 0.656\\P(X= 1)= (^4C_1 *p^1 q^3 )\\P(X=1) = (^4C_1 *0.1^1 0.9^3 ) = 0.2916\\P(X= 2)=( ^4C_2 *p^2 q^2) \\P(X=2) = (^4C_2 *0.1^2 0.9^2 ) = 0.0486\\P(X= 3) = (^4C_3 *p^3 q^3) \\ P(X=3) = (^4C_3 *0.1^3 0.9^1 ) = 0.0036\\P(X= 4) =  (^4C_4 *p^4 q^0 )\\ P(X=4) =(^4C_4 *0.1^4 0.9^0 ) = 0.0001

5 0
3 years ago
Three consecutive even numbers have a sum where one half of that sum is between 90 and 105. Write an inequality to find the the
viva [34]

90 <  [( n + n + 2 + n + 4) / 2] < 105

90 <  (3n + 6) / 2 < 105

3n + 6 > 180      and       3n + 6 <  210

n > 58     ,     n <  68

58  < n < 68   answer


6 0
3 years ago
X = A 21.6 B 12.9 C 9.1
Artist 52 [7]

Answer:

B: 12.9

Step-by-step explanation:

If A B and C are the alternatives, the answer is B: 12.9

The reason is that the hypotenuse can't be smaller than one of its sides, that eliminates alternative C.

And also, the hypotenuse can't be bigger than segments AC + BC, since the side AC is bigger and AC measures 10.8, the hypotenuse would have to measure < 21.6

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6 0
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mariarad [96]

Answer:

No, a regular pentagon does not tessellate.

In a tessellation, all the angles at a point have to add to 360 degrees, as this means there is no overlap, nor are there gaps. To find the interior angle sum of a pentagon, we use the following formula:

(n-2)*180 (where n is the number of sides)

We plug in the number of sides (5) and get:

Angle sum = (5–2)*180

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Regular pentagons have equal sides and equal angles, so to find the size of the interior angle of a pentagon, we divide the angle sum by 5 and get 108 degrees for every angle.

As I said before, the angles at a point need to add up to 360, so we need to know if 108 divides evenly into 360. If it does, the shape tessellates, and, if it doesn’t, the shape does not.

360/108 = 3.33333…

This means that a regular pentagon does not tessellate.

Hope this helps!

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Nesterboy [21]

Answer:

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3 years ago
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