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jok3333 [9.3K]
3 years ago
6

PLEASE HELP!! ILL HIVE BRAINLIEST IF ITS RIGHT!

Mathematics
2 answers:
Nesterboy [21]3 years ago
6 0

Answer:

This would be Helium(He)

Step-by-step explanation:

Its Helium because the bohr model in the picture has 2 electrons.

On the periodic table, it says that Helium has 2 protons which are also equal to electrons

Gnesinka [82]3 years ago
4 0

Answer:

The answer is (He) also known as Helium!

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Determine the domain of the function f(x)=1/3x^2+10x+8
cricket20 [7]
The function is
f(x) = (1/3)x² + 10x + 8

Write the function in standard form for a parabola.
f(x) = (1/3)[x² + 30x] + 8
      = (1/3)[ (x+15)²- 225] + 8
      = (1/3)(x+15)² -75 + 8
f(x) = (1/3)(x+15)² - 67

This is a parabola with vertex at (-15, -67).
The axis of symmetry is x = -15
The curve opens upward because the coefficient of x² is positive.
As x -> - ∞, f -> +∞.
As x -> +∞, f -> +∞
The domain is all real values of x (see the graph below).

Answer: The domain is (-∞, ∞)

8 0
3 years ago
PLEASE HELP-
salantis [7]

Answer:

1 3/4 simplified or 1 12/16 not simplified

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A grocery store bought milk for $2.50 per half gallon and stored it in two refrigerators. During the night, one refrigerator mal
daser333 [38]
In this problem, we let x be the number of half gallons of milk the store bought, and x-12 be the remaining half gallonsWe use the equation profit = revenue-cost
 88.08=4.02(x-12)-2.60x88.08=4.02x-48.24-2.6x1.42x=88.08+48.24=136.32x=136.32/1.42=96Hence, the number of half gallons of milk the store bought is 96
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A student received a coupon for 20% off the total purchase price at a clothing store. Let z be the
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Answer:

i don't know

Step-by-step explanation:

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A tank has the shape of a surface generated by revolving the parabolic segment y = x2 for 0 ≤ x ≤ 3 about the y-axis (measuremen
Darina [25.2K]

Answer:

100\pi\int\limits^9_0 {(\sqrt y)^2(14-y)} \, dy ft-lbs.

Step-by-step explanation:

Given:

The shape of the tank is obtained by revolving y=x^2 about y axis in the interval 0\leq x\leq 3.

Density of the fluid in the tank, D=100\ lbs/ft^3

Let the initial height of the fluid be 'y' feet from the bottom.

The bottom of the tank is, y(0)=0^2=0

Now, the height has to be raised to a height 5 feet above the top of the tank.

The height of top of the tank is obtained by plugging in x=3 in the parabolic equation . This gives,

H=3^2=9\ ft

So, the height of top of tank is, y(3)=H=9\ ft

Now, 5 ft above 'H' means H+5=9+5=14

Therefore, the increase in height of the top surface of the fluid in the tank is given as:

\Delta y=(14-y) ft

Now, area of cross section of the tank is given as:

A(y)=\pi r^2\\r\to radius\ of\ the\ cross\ section

Radius is the distance of a point on the parabola from the y axis. This is nothing but the x-coordinate of the point.

We have, y=x^2

So, x=\sqrt y

Therefore, radius, r=\sqrt y

Now, area of cross section is, A(y)=\pi (\sqrt y)^2

Work done in pumping the contents to 5 feet above is given as:

W=D\int\limits^{y(3)}_{y(0)} {A(y)(\Delta y)} \, dy

Plug in all the values. This gives,

W=100\int\limits^9_0 {\pi (\sqrt y)^2(14-y)} \, dy\\\\W=100\pi\int\limits^9_0 { (\sqrt y)^2(14-y)} \, dy\textrm{ ft-lbs}

7 0
3 years ago
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