4 x ? is close to 105
2 answers:
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Answer:
Area of trapezium = 4.4132 R²
Step-by-step explanation:
Given, MNPK is a trapezoid
MN = PK and ∠NMK = 65°
OT = R.
⇒ ∠PKM = 65° and also ∠MNP = ∠KPN = x (say).
Now, sum of interior angles in a quadrilateral of 4 sides = 360°.
⇒ x + x + 65° + 65° = 360°
⇒ x = 115°.
Here, NS is a tangent to the circle and ∠NSO = 90°
consider triangle NOS;
line joining O and N bisects the angle ∠MNP
⇒ ∠ONS = = 57.5°
Now, tan(57.5°) =
⇒ 1.5697 =
⇒ SN = 0.637 R
⇒ NP = 2×SN = 2× 0.637 R = 1.274 R
Now, draw a line parallel to ST from N to line MK
let the intersection point be Q.
⇒ NQ = 2R
Consider triangle NQM,
tan(∠NMQ) =
⇒ tan65° =
⇒ QM =
QM = 0.9326 R .
⇒ MT = MQ + QT
= 0.9326 R + 0.637 R (as QT = SN)
⇒ MT = 1.5696 R
⇒ MK = 2×MT = 2×1.5696 R = 3.1392 R
Now, area of trapezium is (sum of parallel sides/ 2)×(distance between them).
⇒ A = () × (ST)
= () × 2 R
= 4.4132 R²
⇒ Area of trapezium = 4.4132 R²
Answer: The answer is $2.77.
Step-by-step explanation: Given that we have to pay the loan of $1300 at interest rate of 7.5% in 6 months. According to the table,
Amount for interest in payment 1 = $8.13,
Amount of interest in payment 2 = $6.79
and
Amount of interest in payment 3 = $5.45.
We can see here that the difference in the amounts to be paid in consecutive months will be same, i.e., the payments will form an arithmetic progression (A.P.).
The common difference = 8.13-6.79=6.79-5.45=1.34.
Therefore, amount of interest in payment 4 = $(5.45-1.34) = $4.11
and amount of interest in payment 5 = $(4.11-1.34) = $2.77.
Please see the attached modified table.
Thus, the answer is $2.77.
