Hello,
Equation is y=k(x-1)²-9
and when x=0,y=-6==>-6=k*1²-9==>k=3
y=3(x-1)²-9
when y=0, 3(x-1)²-9=0
==>(x-1-√3)(x-1+√3)=0
x-intercepts are (1+√3,0) and (1-√3,0)
Answer B.
Answer:
All real solutions
Step-by-step explanation:
- The given graph is a maximum quadratic function.
- The solution to the graph is where the graph intersects the x-axis.
- We can see from the graph that, the function intersected the x-axis at two different points, hence its discriminant is greater than zero.
- Hence the solution of g(x) are two distinct real solutions.
- The solutions are not whole numbers because the x-intercepts are not exact.
- The solutions are also not all points that lie on g(x)
- The first choice is correct.
Answer:
I believe the answer is The constant of variation is y is 6 when x is 2.
Answer:
7 5/12
Step-by-step explanation:
3+2=6
2/3 + 3/4 = 8/12 + 9/12 = 17/12 = 1 5/12
1 + 6= 7 5/12
Answer:
B
Step-by-step explanation:
Remark
If you started at W and went all the way around the circle until you wound up back at W, you will have gone 360 degrees. Since the angle measurement that prevents that is 85 degrees, the answer must be 360 - 85 = 275.
