3.01 m/s
This is a simple projectile calculation. What we want is a vertical velocity such that the time the droplet spends going up and going back down to the surface exactly matches the time the droplet takes to travel horizontally 0.800 meters. The time the droplet spends in the air will is:
V*sqrt(3)/2 ; Vertical velocity.
(V*sqrt(3)/2)/9.8 ; Time until droplet reaches maximum height
(V*sqrt(3))/9.8 ; Double that time for droplet to fall back to the surface.
The droplet's horizontal velocity will be:
V/2.
So the total distance the droplet travels will be:
d = (V*sqrt(3))/9.8 * V/2
d = V^2*sqrt(3)/19.6
Let's substitute the desired distance and solve for V
d = V^2*sqrt(3)/19.6
0.8 = V^2*sqrt(3)/19.6
15.68 = V^2*sqrt(3)
15.68/sqrt(3) = V^2
15.68/1.732050808 = V^2
3.008795809 = V
So after rounding to 3 significant figures, the archerfish needs to spit the water at a velocity of 3.01 m/s
Let's verify that answer.
Vertical velocity: 3.01 * sin(60) = 3.01 * 0.866025404 = 2.606736465
Time of flight = 2.606736465 * 2 / 9.8 = 0.531987034 seconds.
Horizontal velocity: 3.01 * cos(60) = 3.01 * 0.5 =
Y = -4/5 + 7, the 7 is the slope intercept and the -4/5 is the slope
Answer:
17 - 4 + 16 - 2
13 + 14
27
Hope it helps!! Good luck on your assignment!! :)
Step-by-step explanation:
You have been given the equation: 17+(-4)-(-16)-2. Remember we can always use tricks to find the equation. Plus times Minus is Minus. Minus times Minus is plus. And Plus times Plus is Minus. I would appreciate if you mark me as brainliest!! :)
Answer:
Step-by-step explanation:
we know hat
<u><em>Vertical Angles</em></u> are the angles opposite each other when two lines cross. They are always congruent.
In this problem
----> by vertical angles
we have
---> given problem
therefore
