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3 years ago

5

‼️GIVING BRAINILEST AND PLEASE DONT SCAM‼️

1 answer:

lidiya [134]3 years ago

3 0

Not trying to spam here but i don’t really know what the question is

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Question 9 (5 points)

Sunny_sXe [5.5K]

to get the equation of any straight line, we simply need two points off of it, let's use those two points from the table in the picture below.

$(\stackrel{x_1}{-4}~,~\stackrel{y_1}{13})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{-17}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-17}-\stackrel{y1}{13}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{(-4)}}} \implies \cfrac{-30}{6 +4} \implies \cfrac{ -30 }{ 10 }\implies -3$

$\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{13}=\stackrel{m}{-3}(x-\stackrel{x_1}{(-4)}) \\\\\\ y-13=-3(x+4)\implies y-13=-3x-12\implies y=-3x+1$

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2 years ago

A survey of the 4700 vehicles on the campus of State University yielded the following circle graph. From the survey, how many ca

Vedmedyk [2.9K]

Answer:

198

Step-by-step explanation:

4 0

3 years ago

The first question. i need help!

solong [7]

Answer:

I didn't know some answers but I wrote the majority of them below!

Step-by-step explanation:

Symmetry of axis: (4, 0)

Vertex: (4, -3)

Domain: 14? (I'm not positive on this one! so sorry)

Range: 14

Min/Max: (4, -3)

I have no clue on the next one!

x-intercepts: (.5, 0) (7.5, 0)

y-intercept: (0, 1)

Then I don't know the last two... I'm sorry I couldn't help you out fully!

8 0

3 years ago

What angle (in radians) corresponds to 0.75 rotations around the unit circle?

polet [3.4K]

3pi/2. The unit circle is 2pi

6 0

3 years ago

The radioactive isotope of lead, Pb-209, decays at a rate proportional to the amount present at time t and has a half-life of 3.

blagie [28]

Answer:

$N(t) =N_o (\frac{1}{2})^{\frac{t}{t_{1/2}}}$

Where $t_{1/2}= 3.3 hr$ represent the half life and the intial amount would be $N_o = 1$

And we want to find the time in order to have a 95% of decay so we can set up the following equation:

$0.05 = 1 (0.5)^{t/3.3}$

If we apply natural log on both sides we got:

$ln(0.05) = \frac{t}{3.3} ln (0.5)$

And solving for t we got:

$t= 3.3 *\frac{ln(0.05)}{ln(0.5)}= 14.26$

So then would takes about 14.26 hours in order to have 95% of the lead to decay

Step-by-step explanation:

For this case we can define the variable of interest amount of Pb209 and for the half life would be given:

$N(t) =N_o (\frac{1}{2})^{\frac{t}{t_{1/2}}}$

Where $t_{1/2}= 3.3 hr$ represent the half life and the intial amount would be $N_o = 1$

And we want to find the time in order to have a 95% of decay so we can set up the following equation:

$0.05 = 1 (0.5)^{t/3.3}$

If we apply natural log on both sides we got:

$ln(0.05) = \frac{t}{3.3} ln (0.5)$

And solving for t we got:

$t= 3.3 *\frac{ln(0.05)}{ln(0.5)}= 14.26$

So then would takes about 14.26 hours in order to have 95% of the lead to decay

4 0

4 years ago