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4 years ago

What is the slope of the line that goes through (-5,5) and (5,-7)

Mathematics

2 answers:

ludmilkaskok [199]4 years ago

8 0

Answer:

A. -1/5

Step-by-step explanation:

-7-(-5) /5-(-5)

= -7+5 / 5+5

= -2/10

-1/5 option A

valkas [14]4 years ago

5 0

Answer:

m=-1/5

Step-by-step explanation:

slope=y2-y1/x2-x2

m=-7-(-5)/5-(-5)

m=-2/10=-1/5

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3 years ago

Use reasoning to solve for the unknown number. five is the quotient of 100 / some number what is the number 5 is the quotient of

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2 years ago

Find the circumference of the circle in terms of pi? [30]

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Step-by-step explanation:

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4 years ago

Read 2 more answers

Write a definite integral that represents the area of the region. (Do not evaluate the integral.) y1 = x2 + 2x + 3 y2 = 2x + 12F

Svet_ta [14]

Answer:

$A = \int\limits^3__-3}{9}-{x^{2}} \, dx = 36$

Step-by-step explanation:

The equations are:

$y = x^{2} + 2x + 3$

$y = 2x + 12$

The two graphs intersect when:

$x^{2} + 2x + 3 = 2x + 12$

$x^{2} = 0$

$x_{1} = 3\\x_{2} = -3$

To find the area under the curve for the first equation:

$A_{1} = \int\limits^3__-3}{x^{2} + 2x + 3} \, dx$

To find the area under the curve for the second equation:

$A_{2} = \int\limits^3__-3}{2x + 12} \, dx$

To find the total area:

$A = A_{2} -A_{1} = \int\limits^3__-3}{2x + 12} \, dx -\int\limits^3__-3}{x^{2} + 2x + 3} \, dx$

Simplifying the equation:

$A = \int\limits^3__-3}{2x + 12}-({x^{2} + 2x + 3}) \, dx = \int\limits^3__-3}{9}-{x^{2}} \, dx$

Note: The reason the area is equal to the area two minus area one is that the line, area 2, is above the region of interest (see image).

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3 years ago

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STALIN [3.7K]

Hope this helps! As long as you keep posting I’ll keep answering- always happy to help!

7 0

3 years ago

Read 2 more answers