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jeka57 [31]
3 years ago
9

What is the slope of the line that goes through (-5,5) and (5,-7)

Mathematics
2 answers:
ludmilkaskok [199]3 years ago
8 0

Answer:

A. -1/5

Step-by-step explanation:

-7-(-5) /5-(-5)

= -7+5 / 5+5

= -2/10

-1/5 option A

valkas [14]3 years ago
5 0

Answer:

m=-1/5

Step-by-step explanation:

slope=y2-y1/x2-x2

m=-7-(-5)/5-(-5)

m=-2/10=-1/5

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If I varies inversely with R and I = 0.25 when R = 18, which equation should be used to show this relationship?
pashok25 [27]
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3 years ago
The area of the shaded segment is 100cm^2. Calculate the value of r.
Reil [10]
Hello, 

The formula for finding the area of a circular region is: A=  \frac{ \alpha *r^{2} }{2}

then:
A_{1} = \frac{80*r^{2} }{2}

With the two radius it is formed an isosceles triangle, so, we must obtain its area, but first we obtain the height and the base.

cos(40)= \frac{h}{r}  \\  \\ h= r*cos(40)\\ \\ \\ sen(40)= \frac{b}{r} \\ \\ b=r*sen(40)

Now we can find its area:
A_{2}=2* \frac{b*h}{2}  \\  \\ A_{2}= [r*sen(40)][r*cos(40)]\\  \\A_{2}= r^{2}*sen(40)*cos(40)

The subtraction of the two areas is 100cm^2, then:

A_{1}-A_{2}=100cm^{2} \\ (40*r^{2})-(r^{2}*sen(40)*cos(40) )=100cm^{2} \\ 39.51r^{2}=100cm^{2} \\ r^{2}=2.53cm^{2} \\ r=1.59cm

Answer: r= 1.59cm
7 0
2 years ago
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