Answer:
A. 11
Step-by-step explanation:
11-3=9
The set does not include 9 because the sign is not underlined so 11 is not a solution.
This gives you three simultaneous equations:
6 = a + c
7 = 4a + c
1 = c
<u>c = 1
</u><u /><u />
If c =1,
6 = a + 1
<u>a = 5
</u><u /><u />
This doesn't work in the second equation, so the quadratic that goes through these points is not in the form y = ax^2 + bx + c
Was there supposed to be a b in the equation?
Answer:
SAS
Step-by-step explanation:
Hope this helps :)
Answer: x=-1
Step-by-step explanation:
Answer:
Yea!
Step-by-step explanation:
