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Sidana [21]
3 years ago
8

You take a 4" high by 6" wide photo. You like it so much that you enlarge it to a 123" wide poster. How tall must the poster be?

Mathematics
1 answer:
Mamont248 [21]3 years ago
7 0

Answer:

82 ''

Step-by-step explanation:

6/123=4/x

6x=4*123

6x=492

x=82

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The function y=-x-3 is graphed only over the domain of (x1-8≤x≤ 8). What is the range of the graph?
irinina [24]

Answer:

B) -5\leq y\leq -1

Step-by-step explanation:

The range is the lowest point to the highest point on the graph.

Remember this:

1. domain (x-axis) LEFT –> RIGHT

2. range BOTTOM (y-axis) –> TOP

when this equation is graphed over the domain, it limits the range to being (8,–5) and (–8,–1) and since with range you only look at the y-coordinates that means that the range is [–5,–1]

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(0.05)(-0.25) = -1.25 <br> True False
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Please solve 21 points plsss help :()
asambeis [7]

Answer:

Answer = 61/157

Step-by-step explanation:

First add all the numbers together.

56 + 61 + 14 + 26 = 157

Then take the number of brown hair and blue eyed people (61) and make a fraction out of all.

61/157

You can not simplify it more than that

Hope this helps

7 0
3 years ago
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Black_prince [1.1K]
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4 0
3 years ago
A box of Georgia peaches has 3 bad and 12 good peaches. (a) If you make a peach cobbler of 12 peaches randomly selected from the
Eddi Din [679]

Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

b) 99.79% probability of having at least 1 bad peach in the peach cobbler

c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

12 good peaches, from a set of 12. So

D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1

Total outcomes:

12 peaches, from a set of 15. So

T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455

Probability:

p = \frac{D}{T} = \frac{1}{455} = 0.0021

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36

Total outcomes:

12 peaches, from a set of 15. So

T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455

Probability:

p = \frac{D}{T} = \frac{36}{455} = 0.0791

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

3 0
3 years ago
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