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Sidana [21]
3 years ago
8

You take a 4" high by 6" wide photo. You like it so much that you enlarge it to a 123" wide poster. How tall must the poster be?

Mathematics
1 answer:
Mamont248 [21]3 years ago
7 0

Answer:

82 ''

Step-by-step explanation:

6/123=4/x

6x=4*123

6x=492

x=82

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IN EXAM NOW PLEASE ANSWER ASAP (CORRECT ANSWER PLEASE 55 POINTS!!!)
Feliz [49]

Answer:

28.07 and rounded to the nearest hundredth would be 28.10

Step-by-step explanation:

6 0
3 years ago
Triangle ABC is graphed below with vertices at A (-4,5), B (-6, -4) and C (4,-4). Use the following rule to produce
guapka [62]

Step-by-step explanation:

A(-4, 5) => A'(-4+2, -5) = A'(-2, -5)

B(-6, -4) => B'(-6+2, -(-4)) = B'(-4, 4)

C(4, -4) => C'(4+2, -(-4)) = C'(6, 4)

Hence the new coordinates are A'(-2, -5), B'(-4, 4) and C'(6, 4).

7 0
3 years ago
What is thr answer of (a-b) (a+2b)​
kari74 [83]

Answer:

Step-by-step explanation:

Use FOIL method

F -> First

O Outside

I inside

L Last

(a - b)(a + 2b)= a*a + a *2b + (-b)*a + (-b)*2b

                     = a² + <u>2ab - ab</u> - 2b²

Combine like terms

                       = a² + ab - 2b²

3 0
3 years ago
the sum of the speeds of two trains is 716.7 miles per hour if the speed of the first train is 5.3 miles per hour faster than a
Nimfa-mama [501]
The best way to solve this is to make an algebraic expression to represent the situation~
If x is the speed of the first train and y is the speed of the second we can make 716.7 = x + y
the first train is 5.3 mph faster so x = y + 5.3
Now we can replace x with our new value to get 716.7 = y + (y+5.3)
Simplify and we get 716.7 = 2y + 5.3
Now all we got to do is simplify this equation, 716.7 - 5.3 = 711.4. Divide by 2 to get 355.7 for the speed of the second train. Since the first train is 5.3 mph faster, we add that to the second trains value and get our answer. The first train is going at 361.7, the second at 355.7
5 0
3 years ago
PLEASE PLEASE HELP<br><br>question is attached
Andreas93 [3]
Short Answer
x1 = 4.8284
x2 = - 0.828
Remark
Substitute the value for y from the first equation into the second equation. Multiply by 4 and then see if it factors out. Solve for x first and then y. 

Step one 
Solve for y in the first equation. Subtract x from both sides.
y = 2 - x

Step Two
Equate the two ys.
2 - x = - 1/4x^2 + 3

Step Three
Bring the left side over to the right side.
0 = -1/4 x^2 + x + 3 -  2 Combine the like terms.
0 = -1/4 x^2 + x + 1      

Step Four
0 = -1/4 x^2 + x + 1      Multiply through by 4
0 = - x^2 + 4x + 4

Step five
This won't factor. The only thing you can do is use the quadratic equation for roots.

a = - 1
b = 4
c = 4

\text{x = }\dfrac{ -b \pm \sqrt{b^{2} - 4ac} }{2a}

\text{x = }\dfrac{ -(4) \pm \sqrt{4^{2} - 4(-1)4}}{-2}

\text{x = }\dfrac{ -(4) \pm \sqrt{16 + 16}}{-2}

\text{x = } 2 \pm \sqrt{32 }\div -2

x = 2 +/- sqrt(4^2 * 2) / (- 2)

x = 2 +/- 4 sqrt(2) / - 2
x = 2 -/+ 2 sqrt(2)
x = 2 -/+ 2 *(1.414) 
x = 2 -/+ 2.828

x1 = 4.8284
x2 = - 0.828
4 0
4 years ago
Read 2 more answers
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