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3 years ago

* Find the area of a triangle: Base of 8 cm Hight of 9 cm

Mathematics

1 answer:

Sliva [168]3 years ago

5 0

Answer:

36 cm

Step-by-step explanation:

The formula to find the area of a triangle is A=1/2bh where b stands for base and h for height.

So, 8 times 9 equals 72, and 72 divided by 2 is 36.

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In an election, about 500,000 people voted in all. What could be the exact number of people who voted in the election?

elixir [45]

I am going to give a few answers:

497,543
504,690
501,991
496,900

6 0

3 years ago

One of the main contaminants of a nuclear accident, such as that at Chernobyl, is strontium-90, which decays exponentially at a

igor_vitrenko [27]

Answer: $P=0.975^t$

Step-by-step explanation:

We know that the general form of the exponential decay formula is

$y=A(1-r)^t$ , where y is final amount remaining after t time, A is the original amount and r is the rate of decay

Now, the ratio of strontium-90 remaining, p , as a function of years, t , since the nuclear accident. $P=\frac{A(1-0.02)^t}{A}=\frac{(0.975)^t}{1}$

Hence, the ratio of remaining since the nuclear accident is $P=0.975^t$

3 0

3 years ago

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Reptile [31]

Answer:

The real zeros of f(x) are x = 0.3 and x = -3.3.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this problem, we have that:

$f(x) = x^{2} + 3x - 1$

$a = 1, b = 3, c = -1$

$\bigtriangleup = 3^{2} - 4*1*(-1) = 13$

$x_{1} = \frac{-3 + \sqrt{13}}{2*1} = 0.3$

$x_{2} = \frac{-3 - \sqrt{13}}{2*1} = -3.3$

The real zeros of f(x) are x = 0.3 and x = -3.3.

7 0

3 years ago

What is the value of c such that the line y=2x+3 is tangent to the parabola y=cx^2

satela [25.4K]

The value of $c$ such that the line $y = 2\cdot x + 3$ is tangent to the parabola $y = c\cdot x^{2}$ is $-\frac{1}{3}$ .

If $y = 2\cdot x + 3$ is a line <em>tangent</em> to the parabola $y = c\cdot x^{2}$ , then we must observe the following condition, that is, the slope of the line is equal to the <em>first</em> derivative of the parabola:

$2\cdot c \cdot x = 2$ (1)

Then, we have the following system of equations:

$y = 2\cdot x + 3$ (1)

$y = c\cdot x^{2}$ (2)

$c\cdot x = 1$ (3)

Whose solution is shown below:

By (3):

$c =\frac{1}{x}$

(3) in (2):

$y = x$ (4)

(4) in (1):

$y = -3$

$x = -3$

$c = -\frac{1}{3}$

The value of $c$ such that the line $y = 2\cdot x + 3$ is tangent to the parabola $y = c\cdot x^{2}$ is $-\frac{1}{3}$ .

We kindly invite to check this question on tangent lines: brainly.com/question/13424370

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2 years ago

PLEASE HELP! I'M STRUGGLING! WILL GIVE BRAINLIEST

lianna [129]

Answer:

1/6

Step-by-step explanation:

Since there is only 1 letter R in 6 options it is 1/6 (im not entirely sure)

7 0

3 years ago

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