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Jlenok [28]
2 years ago
5

Please help I don’t understand how to do this

Mathematics
1 answer:
horsena [70]2 years ago
5 0

Answer:

DOC = 70

BOC = 110

AOD = 110

Step-by-step explanation:

AOB is supplementary to BOC and AOD, which means together they equal 180. 180-70=110, so BOC and AOD are both 110.

AOB and DOC are vertical angles to each other, so are AOD and BOC. Vertical angles are always equal to each other. So since AOB is 70, so is DOC.

Hope this makes sense:)

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Last year, Shantell bought a car for $24,000. The current value of the car is $21,000. Find the percent decrease in the value of
Morgarella [4.7K]
<span>Last year, Shantell bought a car for 24 000 dollars. It decreases to 21 000 dollars this current year.
Let’s find for the percentage that it decreased.
=> in 24 000 the 50% is 12 000 as we all know since it’s divided by 2. So meaning, the possible answer is less than 50%.
=> now 25% of 24 000 is 6 000, and the amount that we’re looking is 3000, thus, the answer is 12.5%
=> 24 000 * 0.125 = 3000
=> 24 000 – 3000 = 21 000</span>



4 0
2 years ago
Homework #16- Complete all odd questions.
katen-ka-za [31]

                                                      Question 1)

Given

The expression is 5xy

To determine

Find the value of 5xy if x = 2 and y = 3

5xy

substitute x = 2 and y = 3

5xy = 5(2)(3)

      = 5(6)

      = 30

Therefore, the value of 5xy = 30 if x = 2 and y = 3.

<em>Note: your remaining questions are not mentioned. But, the procedure may remain the same. Hopefully, your concept will be cleared anyway.</em>

8 0
2 years ago
Offering 15 points please help
mario62 [17]

Answer:

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Step-by-step explanation:

6 0
3 years ago
F(x) = 2x^2+ 5x + 20<br><br> Find f(-9)
8_murik_8 [283]

Answer:

137

Step-by-step explanation:

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162-45+20

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8 0
3 years ago
the graph of y=e^tanx-2 crosses the x axis at one point in the interval [0,1]. What is the slope of the graph at this point? I g
Svetlanka [38]
Y = e^tanx   -   2

To find at which point it crosses x axis we state that y= 0

e^tanx   - 2 = 0 
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tanx = 0.69314
x = 0.6061

to find slope at that point first we need to find first derivative of funtion y.

y' = (e^tanx)*1/cos^2(x)

now we express x = 0.6061 in y' and we get:
y' = k = 2,9599
3 0
2 years ago
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