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3 years ago

WHATS THE AREA?? PLEASE HELP!

Mathematics

1 answer:

pentagon [3]3 years ago

8 0

(0.5*10*18) + (0.5*6*18)
= 54 + 90
= 144 square units

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PLEASE PLEASE HELP ME OUT! But i ask that you explain how you got your answer and not just give the answer.

rjkz [21]

ok so first we would do the function d(x) = 3(8)+2

which when solved turns out to be 26

we would then do the function h(x) = 2(26) +7

which when solved turns out to be 59

so he would need 59 dollars for the donuts

6 0

3 years ago

Three classes. Of third graders are going to the zoo. Ms. Noels class has 10 students. Mr. Grubbs class has 9 students, and Ms.

liq [111]

Answer:

If the children divide evenly onto 3 buses, there will be 11 children on each bus

Step-by-step explanation:

Add all 3 classes to ind total amount of students

Ms. Noels class has 10 students

Mr. Grubbs class has 9 students

Ms. Ackerman's class has 14 students

Total Students: 10 students + 9 students + 14 students

33 total students

Dividing 33 students in 3 busses is 33 / 3 which equals 11

4 0

2 years ago

At a university, 60% of the 7,400 students are female. The student newspaper reports the results of a survey of a random sample

omeli [17]

Given Information:

Population mean = p = 60% = 0.60

Population size = N = 7400

Sample size = n = 50

Required Information:

Sample mean = μ = ?

standard deviation = σ = ?

Answer:

Sample mean = μ = 0.60

standard deviation = σ = 0.069

Step-by-step explanation:

We know from the central limit theorem, the sampling distribution is approximately normal as long as the expected number of successes and failures are equal or greater than 10

np ≥ 10

50*0.60 ≥ 10

30 ≥ 10 (satisfied)

n(1 - p) ≥ 10

50(1 - 0.60) ≥ 10

50(0.40) ≥ 10

20 ≥ 10 (satisfied)

The mean of the sampling distribution will be same as population mean that is

Sample mean = p = μ = 0.60

The standard deviation for this sampling distribution is given by

$\sigma = \sqrt{\frac{p(1-p)}{n} }$

Where p is the population mean that is proportion of female students and n is the sample size.

$\sigma = \sqrt{\frac{0.60(1-0.60)}{50} }\\\\\sigma = \sqrt{\frac{0.60(0.40)}{50} }\\\\\sigma = \sqrt{\frac{0.24}{50} }\\\\\sigma = \sqrt{0.0048} }\\\\\sigma = 0.069$