1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Crank
2 years ago
8

if the cost of 3 chocolates and 2 cookies is $22 and that of 2 chocolates and 3 cookies is $18, what is the cost of cookies.​

Mathematics
2 answers:
Vanyuwa [196]2 years ago
4 0

Answer:$2

Step-by-step explanation:Express as two equations . Lex x Be chocolate and y be cookies.

3x+2y=22

2x+3y= 18

Common factor of 6 so times first ran by 2, second ran by 3 . Eliminate.

ycow [4]2 years ago
4 0

Answer:

$2

Step-by-step explanation:

Let the cost of a chocolate and a cookie be $x and $y respectively.

Using the given information, form 2 equations and label them.

3x +2y= 22 -----(1)

2x +3y= 18 -----(2)

Now let's try to multiply both equations by a certain integer, such that the coefficient of x in both equations are the same. This allows us to eliminate the x term through subtraction.

(1) ×2:

6x +4y= 44 -----(3)

(2) ×3:

6x +9y= 54 -----(4)

(4) -(3):

6x +9y -(6x +4y)= 54 -44

Expand, simplify:

6x +9y -6x -4y= 10

5y= 10

Dividing both sides by 5:

y= 10 ÷5

y= 2

Thus, a cookie costs $2.

Note:

• Since we are only trying to find the value of y (cost of cookie), it is faster to eliminate the x term.

• If the signs of the coefficient of the term is opposite (e.g. -6 and 6), we can eliminate the term through addition.

Example:

-6x +4y= 44 -----(1)

6x +9y= 54 -----(2)

(1) +(2):

-6x +4y +6x +9y= 44 +54

13y= 98

y= 98 ÷13

y= 7.54 (3 s.f.)

You might be interested in
14. Danny works part-time at Tom's Toy Store. He
jarptica [38.1K]

Answer:

  • 21 hours in May, 63 hours in June

Step-by-step explanation:

<h3>Set up equations</h3>
  • m - May, j - June
  • m + j = 84
  • m = 1/3j
<h3>Solve by substitution, fin the value of j</h3>
  • 1/3j + j = 84
  • 4/3j = 84
  • j = 84*3/4
  • j = 63
<h3>Find m</h3>
  • m + 63 = 84
  • m = 84 - 63
  • m = 21
5 0
2 years ago
The circle below is centered at the origin and has a radius of 4. What is its
BlackZzzverrR [31]

Answer:

Step-by-step explanation:

The standard form of a circle's equation is

(x-h)^2+(y-k)^2=r^2 where h and k are the circle's center and r is the radius. We are told, and we can see, that the center of the circle is (0, 0) so h = 0 and k = 0. The radius, given as 4, goes into the equation squared, so the equation is

(x-0)^2+(y-0)^2=16 which simplifies down to

x^2+y^2=16, choice C.

8 0
3 years ago
Read 2 more answers
Plz answer it has to be done by 9:00
LiRa [457]
The answer will be 7 bean bags

7 0
3 years ago
Read 2 more answers
Please help! serious answers only
vovangra [49]
I believe also 115 degrees bc they’re vertical angles
5 0
2 years ago
Read 2 more answers
I need a answer to equation -2x=8
valkas [14]

Answer:

x = -4

Step-by-step explanation:

Divide both sides by -2.

x= - 8/2

Simplify - 8/2 to -4.

4 0
3 years ago
Other questions:
  • Find the surface area of the triangular prism shown ​
    15·1 answer
  • Solve for x: 2 over 5 (x - 4) = 2x
    5·1 answer
  • Which polynomial below is considered a binomial? Question 3 options:
    10·1 answer
  • A recipie calls for 2 3/4 cups of milk. How many cups of milk,written asa fraction greater than one,are used in the recipie.
    14·2 answers
  • What is 2550 gallons in 30 days in unit rate
    14·1 answer
  • Which phase best describes the transition from the graph y=2x^2 to the graph of y2x^2+5?
    13·1 answer
  • 9/2 divided by 3/4<br> I’m taking a test rn so please answer
    8·2 answers
  • I WILL LITERALLY LOVE YOU THIS IS DUE TONIGHT PLEASEEE
    9·1 answer
  • Write an equation in point-slope form of the line that passes through the given point and with the given slope m.
    7·1 answer
  • Christine exercises more than 40 minutes per day.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!