Ideal Gas Law equation: PV= nRT
⇒ V= nRT/ P
⇒ V= (1.50 mol)* (0.08206 L*atm/ (K*mol))* 273 K/ 1.00 atm= 33.6 L.
The final answer is 33.6 L.
Hope this helps~
5.57 × 10²⁵ molecules of Br₂ will have a mass of 14862.33g
HOW TO CALCULATE MASS:
- The mass of an element can be calculated by multiplying the number of moles by its molar mass. That is;
mass (g) = moles (mol) × molar mass (g/mol)
- However, the number of moles in 5.57 × 10²⁵ molecules of Br₂ will be calculated first by dividing the number of molecules by Avogadro's number.
no. of moles = 5.57 × 10²⁵ ÷ 6.02 × 10²³
no. of moles = 5.57/6.02 × 10²⁵-²³
no. of moles = 0.93 × 10²
no of moles = 93 moles
Molar mass of Br₂ = 159.81g/mol
Mass of Br₂ = 93 × 159.81
Mass of Br₂ = 14862.33g
- Therefore, 5.57 × 10²⁵ molecules of Br₂ will have a mass of 14862.33g.
Learn more: brainly.com/question/10384503?referrer=searchResults
Answer:
1.63ₓ10⁻⁶ g of U
139.03 g of H
0.385 g of O
141.8 g of Pb
Explanation:
In first place, we need to convert the number of atoms to moles, as we know that 1 mol of anything occupies 6.02×10²³ particles
Therefore:
4.12×10¹⁵ atoms of U . 1 mol / 6.02×10²³ atoms = 6.84×10⁻⁹ moles of U
8.37×10²⁵ atoms of H . 1 mol /6.02×10²³ atoms = 139.03 moles of H
1.45×10²² atoms of O . 1 mol /6.02×10²³ atoms = 0.0241 moles of O
4.12×10²³ atoms of Pb . 1 mol /6.02×10²³ atoms = 0.684 moles of Pb
Moles . Molar mass = Mass (g)
6.84×10⁻⁹ moles of U . 238.03 g/mol = 1.63ₓ10⁻⁶ g of U
139.03 moles of H . 1 g/mol = 139.03 g of H
0.0241 moles of O . 16 g/mol = 0.385 g of O
0.684 moles of Pb . 207.2 g/mol = 141.8 g of Pb
I don't know what model you're referring to so I can't answer the question. However, upon researching, I found a similar problem. I posted it as an attached picture. Looking at the model, the amount of grams a herbivore eat each day corresponds to the arrow pointing inwards. Since the label says 4.0 g,
<em>the answer is 4 g per day</em>.