Answer:
All of the above answers are correct.
Explanation:
Double bonds are stronger that single bonds because they have both sigma and pi bonds whereas single bonds contain only sigma bond. They also involve the sharing of electron pairs and heavily imparts rigidity to a molecule.
Answer:
Matter cannot be created or destroyed in chemical reactions. This is the law of conservation of mass. In every chemical reaction, the same mass of matter must end up in the products as started in the reactants. Balanced chemical equations show that mass is conserved in chemical reactions.
Explanation:
hope this help :)
Answer:
Option A. 1191.49 K
Explanation:
Data obtained from the question include:
The equation for the reaction is given below:
4HCl + O2 —> 2Cl2 + 2H2O
Enthalpy (H) = +280 KJ/mol = +280000 J/mol
Entropy (S) = +235 J/Kmol
Temperature (T) =..?
The temperature at which the reaction will be feasible can be obtained as follow:
Change in entropy (ΔS) = change in enthalphy (ΔH)/T
(ΔS) = (ΔH)/T
235 = 280000/T
Cross multiply
235 x T = 280000
Divide both side by 235
T = 280000/235
T = 1191.49 K
Therefore, the temperature at which the reaction will be feasible is 1191.49 K
Answer:
The change in entropy of the surrounding is -146.11 J/K.
Explanation:
Enthalpy of formation of iodine gas = 
Enthalpy of formation of chlorine gas = 
Enthalpy of formation of ICl gas = 
The equation used to calculate enthalpy change is of a reaction is:
![\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]](https://tex.z-dn.net/?f=%5CDelta%20H_%7Brxn%7D%3D%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H_f%28product%29%5D-%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H_f%28reactant%29%5D)
For the given chemical reaction:
The equation for the enthalpy change of the above reaction is:
![\Delta H_{rxn}=[(2\times \Delta H_f_{(ICl)})]-[(1\times \Delta H_f_{(I_2)})+(1\times \Delta H_f_{(Cl_2)})]](https://tex.z-dn.net/?f=%5CDelta%20H_%7Brxn%7D%3D%5B%282%5Ctimes%20%5CDelta%20H_f_%7B%28ICl%29%7D%29%5D-%5B%281%5Ctimes%20%5CDelta%20H_f_%7B%28I_2%29%7D%29%2B%281%5Ctimes%20%5CDelta%20H_f_%7B%28Cl_2%29%7D%29%5D)
![=[2\times 17.78 kJ/mol]-[1\times 0 kJ/mol+1\times 62.436 kJ/mol]=-26.878 kJ/mol](https://tex.z-dn.net/?f=%3D%5B2%5Ctimes%2017.78%20kJ%2Fmol%5D-%5B1%5Ctimes%200%20kJ%2Fmol%2B1%5Ctimes%2062.436%20kJ%2Fmol%5D%3D-26.878%20kJ%2Fmol)
Enthaply change when 1.62 moles of iodine gas recast:
Entropy of the surrounding = 
1 kJ = 1000 J
The change in entropy of the surrounding is -146.11 J/K.
Answer:
<em>2NaOH+ H2SO4 → Na2SO4 + 2H2O</em>
<h3>I HOPE ITS RIGHT IF NOT THEN SORRY</h3>
HAVE A GREAT DAY :)
