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liraira [26]
3 years ago
8

8,000,000 + 300+ 9 in standard form

Mathematics
2 answers:
expeople1 [14]3 years ago
6 0

I believe the answer you are looking for is 8,000,309

If not, lmk

Delicious77 [7]3 years ago
4 0

8,000,309----------------------

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3 years ago
7. A large population of ALOHA users manages to generate 60 requests/s, including originals and retransmissions. Time is slotted
Debora [2.8K]

Answer:

P(success at first attempt) = 0.1353

Step-by-step explanation:

This question follows poisson distribution. Thus, the formula is;

P(k) = (e^(-G) × (G)k)/k!

where;

G is number of frames generated in one frame transmission time(or frame slot time)

Let's find G.

To do this, we need to find number of frames generated in 1 slot time which is given as 50 ms.

Now, in 1000 ms, the number of frames generated = 50

Thus; number of frames generated in 50 ms is;

G = (50/1000) × 50

G = 2.5

To find the chance of success on the first attempt will be given by;

P(success at first attempt) = P(0) = e^(-G) = e^(-2) = 0.1353

8 0
3 years ago
The table shows the number of calories in four meals and the cost of each meal.
Aleksandr-060686 [28]

Answer:

A weak negative correlation

Step-by-step explanation:

correlation, r = \frac{∑(y-\alpha)(x-\beta  }{\sqrt{∑(y-\alpha)^2∑(x-\beta )^2 } }

where,

\alpha = \frac{∑y}{n} \\\beta =\frac{∑x}{n} \\∑ = summation

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therefore,\\\\r= -0.12924

This represents a weak negative correlation

6 0
3 years ago
Read 2 more answers
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8090 [49]

Answer:

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Step-by-step explanation:

Rachel earned $34 in 4 hours at her job today. It means we can find his earning in 1 hour.

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= $8.5

He earns $8.5 in an hour.

To find his earning in 10 hours, multiply $8.5 by 10. So,

Earning =  $8.5 × 10

= $85

Hence, Rachel earn $85 in 10 hours.

8 0
4 years ago
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Kobotan [32]
To solve this we use trigonometric functions that would relate the hypotenuse y and the given values. For this case we use cosine function which is expressed as:

cosine theta = adjacent side / hypotenuse
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y = 35 / cos 52
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7 0
3 years ago
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