Question

Find the surface area of a cylinder with a base radius of 2 cm and a height of 8 cm

Answer 1

Answer:

82.6cm2

Step-by-step explanation:

$\pi {r}^{2} + \pi {r}^{2} + 2 \pi \: r h$

$\pi = \frac{22}{7}$

radius =2cm

height=8cm

$( \frac{22}{7} \times 2 \times 2 )+ ( \frac{22}{7} \times 2 \times 2) + (2 \times \frac{22}{7} \times 2 \times 8)$

Multiplying the numerators and The whole numbers, we have

$\frac{88}{7} + \frac{88}{7} + \frac{402}{7}$

Since the denominators of the fractions are the same, we add the numerators.

$\frac{88 + 88 + 402}{7} = \frac{578}{7} \\ which \: becomes$

$82.57{cm}^{2} = 82.6 {cm}^{2}$