When considering your financial situation, you should consider ——

Schach [20]

Answer:

add 200 shillings to the book balance

8 0

3 years ago

The Yale Company has one bond outstanding. The bond has a $20,000 face value and matures in 20 years. The bond makes no interest

natima [27]

Answer:

$16,695.11

Explanation:

the price of the bond is equal to the present value of its cash flows:

value of cash flows in year 6 = $1,100 x 12.75523 (PV annuity factor, 16 periods, 2.8%) = $14,030.75

value of cash flows in year 14 = $1,400 x 10.07390 (PV annuity factor, 12 periods, 2.8%) = $14,103.46

present value in year 0 = [$14,030.75 / 1.056⁶] + [$14,103.46 / 1.056¹⁴] = $10,118.06 + $6,577.05 = $16,695.11

8 0

3 years ago

The purpose of the Uniform Franchise Offering Circular is to

goldfiish [28.3K]

I think it’s b it is the most right played out

5 0

3 years ago

A. how can you make your motor run in reverse? make sure to try it.

Reika [66]

<span>You can make the motor run move backward by flipping the magnet on the other side in such a way that the side of contrary charge is now covering towards the motor.</span>

Most electric motors work through the communication between an electric motor's magnetic field and twisting streams to produce compel. In specific applications, for example, in regenerative braking with footing engines in the transportation business, electric engines can likewise be utilized as a part of turn around as generators to change over mechanical vitality into electric power<span>.</span>

5 0

4 years ago

The Cobb-Douglas production function is given by

Pani-rosa [81]

Answer:

If the Cobb Douglas production funtion is $Q(\lambda{K},\lambda{L})=A(\lambda{K})^{1.4}\times(\lambda{L})^{1.6}$

This function is homogeneous of degree 3: To understand that, we first must know that a function f(K,L) is homogeneous of degree "m" if $f(\lambda L,\lambda K)}=\lambda ^{m}f(L,K)\,$ . Intuitively, this means that, when you increase your productive factors (in this case, we are talking about a production function), by a factor " $\lambda$ ", your output increases by $\lambda^m$ . Depending on the value of m, the function will exhibit increasing returns to scale (m>1), decreasing returns to scale (m<1) or returns to scale equal to 1 (when m=1).

In this case, $Q(\lambda{K},\lambda{L})=A(\lambda{K})^{1.4}\times(\lambda{L})^{1.6}$ . Applying distributive power's property, we get $Q(\lambda{K},\lambda{L})=A(\lambda{K})^{1.4}\times(\lambda{L})^{1.6}=A(\lambda^{1.4})K^{1.4}\times(\lambda^{1.6})L^{1.6}$ .
Because of power property, we can associate terms and get $Q(\lambda{K},\lambda{L})=A(\lambda^{1.4})K^{1.4}\times(\lambda^{1.6})L^{1.6}=A(\lambda^3)K^{1.4}L^{1.6}$ (remember that $\lambda^{1.4}\times\lambda^{1.6}=\lambda^{(1.4+1.6)}=\lambda^3$ .
Finally, $Q(\lambda{K},\lambda{L})=A(\lambda{K})^{1.4}\times(\lambda{L})^{1.6}=\lambda^3AK^{1.4}L^{1.6}$ . In this case the function is homogeneous of degree 3 because when multiplying K and L by $\lambda$ , the function as a whole is multiplied by $\lambda^3$ .

Euler's Theorem: this theorem states that, if a function is homogeneous of degree "m", the following must hold: $L\frac{\partial Q}{\partial L} +K\frac{\partial Q}{\partial K}= m\times{Q(K,L)}$ .

To prove it, we should then calculate the partial derivative of Q with respect to L and K respectively, and apply the previous definition to see if the statement holds.

$\frac{\partial{Q}}{\partial{K}}=1.4\times{A}K^{0.4}L^{1.6}$

$\frac{\partial{Q}}{\partial{L}}=1.6\times{A}K^{1.4}L^{0.6}$

Applying Euler's Theorem then means $K(1.4\times{A}K^{0.4}L^{1.6})+L(1.6\times{A}K^{1.4}L^{0.6})$ should be equal to $3Q(\lambda{K},\lambda{L})=3A(\lambda{K})^{1.4}\times(\lambda{L})^{1.6}$ (remember that in this case, m=3, see previous exercise).

Solving $K(1.4\times{A}K^{0.4}L^{1.6})+L(1.6\times{A}K^{1.4}L^{0.6})=1.4(AK^{1.4}L^{1.6})+1.6(AK^{1.4}L^{1.6})=3\times(AK^{1.4}L^{1.6})=3\times{Q(K,L)}$

Then the Euler's Theorem is verified!

7 0

3 years ago

When considering your financial situation, you should consider ———