Answer:
6
Step-by-step explanation:
Speed = Distance/time
Therefore time must = distance/speed
Since the two students are running apart from eachother, we can add their speeds together.
Also we can subtract 10 feet from our goal of 1870 since they're already 10 feet apart.
1860 feet/(150+1650) feet per minute
We can cancel out the feet since it's a common term.
And we're left with 6 minutes.
Answer:
#1 is -9
#2 is 3
Step-by-step explanation:
-9x3 is -27 then add 10 to that you get -17
5x3 is 15 then subtract 1 and you get 14
His first payment is $100, thus a₁ = 100.
the next "term", month will be 1.1 times more than the one before, namely r = 1.1, the common ratio.


is the serie divergent or convergent?
well, to make it short, when the common ratio is 0 < | r | < 1, namely a fraction between 0 and 1, only then the serie is convergent, namely it reaches a fixed value, now in this case, 1.1 is a value larger than anything between 0 and 1, so no dice.
Answer:
The order is "D, B, A, E, C".
Step-by-step explanation:
The numbers are as follows:
![A=\frac{2^{1/2}}{4^{1/6}}\\\\B = \sqrt[12]{128}\\\\C=(\frac{1}{8^{1/5}})^{2}\\\\D = \sqrt{\frac{4^{-1}}{2^{-1}\cdot 8^{-1}}}\\\\E = \sqrt[3]{2^{1/2}}\cdot 4^{-1/4}](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B2%5E%7B1%2F2%7D%7D%7B4%5E%7B1%2F6%7D%7D%5C%5C%5C%5CB%20%3D%20%5Csqrt%5B12%5D%7B128%7D%5C%5C%5C%5CC%3D%28%5Cfrac%7B1%7D%7B8%5E%7B1%2F5%7D%7D%29%5E%7B2%7D%5C%5C%5C%5CD%20%3D%20%5Csqrt%7B%5Cfrac%7B4%5E%7B-1%7D%7D%7B2%5E%7B-1%7D%5Ccdot%208%5E%7B-1%7D%7D%7D%5C%5C%5C%5CE%20%3D%20%5Csqrt%5B3%5D%7B2%5E%7B1%2F2%7D%7D%5Ccdot%204%5E%7B-1%2F4%7D)
Simplify the value of A, B, C, D and E as follows:
![A=\frac{2^{1/2}}{4^{1/6}}=\frac{2^{1/2}}{2^{2/6}}=\frac{2^{1/2}}{2^{1/3}}=2^{1/2-1/3}=2^{1/6}=1.1225\\\\B = \sqrt[12]{128}=(128)^{1/12}=(2^{7})^{1/12}=2^{7/12}=1.4983\\\\C=(\frac{1}{8^{1/5}})^{2}=(\frac{1}{(2^{3})^{1/5}})^{2}=(\frac{1}{2^{3/5}})^{2}=\frac{1}{2^{3/5\times2}}=\frac{1}{2^{6/5}}=2^{-6/5}=0.4353\\\\D = \sqrt{\frac{4^{-1}}{2^{-1}\cdot 8^{-1}}}=\sqrt{\frac{2^{-2}}{2^{-1}\cdot 2^{-3}}}=\sqrt{2^{-2+1+3}}=2\\\\E = \sqrt[3]{2^{1/2}}\cdot 4^{-1/4}= (2^{1/2})^{1/3}\cdot 2^{-2/4}=2^{-1/3}=0.7937](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B2%5E%7B1%2F2%7D%7D%7B4%5E%7B1%2F6%7D%7D%3D%5Cfrac%7B2%5E%7B1%2F2%7D%7D%7B2%5E%7B2%2F6%7D%7D%3D%5Cfrac%7B2%5E%7B1%2F2%7D%7D%7B2%5E%7B1%2F3%7D%7D%3D2%5E%7B1%2F2-1%2F3%7D%3D2%5E%7B1%2F6%7D%3D1.1225%5C%5C%5C%5CB%20%3D%20%5Csqrt%5B12%5D%7B128%7D%3D%28128%29%5E%7B1%2F12%7D%3D%282%5E%7B7%7D%29%5E%7B1%2F12%7D%3D2%5E%7B7%2F12%7D%3D1.4983%5C%5C%5C%5CC%3D%28%5Cfrac%7B1%7D%7B8%5E%7B1%2F5%7D%7D%29%5E%7B2%7D%3D%28%5Cfrac%7B1%7D%7B%282%5E%7B3%7D%29%5E%7B1%2F5%7D%7D%29%5E%7B2%7D%3D%28%5Cfrac%7B1%7D%7B2%5E%7B3%2F5%7D%7D%29%5E%7B2%7D%3D%5Cfrac%7B1%7D%7B2%5E%7B3%2F5%5Ctimes2%7D%7D%3D%5Cfrac%7B1%7D%7B2%5E%7B6%2F5%7D%7D%3D2%5E%7B-6%2F5%7D%3D0.4353%5C%5C%5C%5CD%20%3D%20%5Csqrt%7B%5Cfrac%7B4%5E%7B-1%7D%7D%7B2%5E%7B-1%7D%5Ccdot%208%5E%7B-1%7D%7D%7D%3D%5Csqrt%7B%5Cfrac%7B2%5E%7B-2%7D%7D%7B2%5E%7B-1%7D%5Ccdot%202%5E%7B-3%7D%7D%7D%3D%5Csqrt%7B2%5E%7B-2%2B1%2B3%7D%7D%3D2%5C%5C%5C%5CE%20%3D%20%5Csqrt%5B3%5D%7B2%5E%7B1%2F2%7D%7D%5Ccdot%204%5E%7B-1%2F4%7D%3D%20%282%5E%7B1%2F2%7D%29%5E%7B1%2F3%7D%5Ccdot%202%5E%7B-2%2F4%7D%3D2%5E%7B-1%2F3%7D%3D0.7937)
Arrange the following numbers in increasing order as follows:
D > B > A > E > C
Thus, the order is "D, B, A, E, C".
A = x^2 + 6x - 27 A = x^2 + 9x - 3x - 27 A = x(x+9)-3(x+9) A = (x+9)(x-3) A = lw l = (x+9) w =(x-3)