Can someone please help me

20. The total mass of three boxes, A, B, and C, is 1.95 kg. The mass of Box A is 700 g. The mass of Box B is 4 times the mass of

Ksju [112]

Answer:

Step-by-step explanation:

LET'S DO THIS!

Total mass of A, B and C = 1.95kg

Mass of A = 700 kg

Mass of B = 4x the mass of c (4 x C) which is 4c

Mass of C = ? ( let's call it C )

<h3>Adding all together </h3>

700 + 4c + C = 1.95

<h3>Add like terms</h3>

700 + 5C = 1.95

5C = 1.95 - 700

5C = -698.05

C = -698.05 ÷ 5

<h3>To find B now </h3><h3>Remember they said B is 4 times the mass of C and C = -139.61</h3>

therefore B = 4 × -139.61

<h3>To check if we are correct, we add the masses of A, B and C to see if it equals their total mass which is 1.95kg</h3>

<h3>Using your calculator: </h3>

= 700 + ( -558.44 ) + ( -139.61 )

= 700 - 558.44 -139.61

= 1.95 kg

Which makes us CORRECT ✅.

<h3>Hope this helps.</h3><h3>Good luck ✅.</h3>

5 0

2 years ago

Read 2 more answers

Drag each number to the correct location on the table.

ASHA 777 [7]

Answer:

$\text{Rational number} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{ Irrational number}$

$3\sqrt{25} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \sqrt{141}\\\\\sqrt{256} \\\\1. \overline{ 1625} \\\\\frac{-11}{151}$

Step-by-step explanation:

Since we believe it

The number sequence is that those which can be described as $\frac{p}{q}$ and that is not ending and recurring. Figures that are unreasonable are also the ones, that are not $\frac{p}{q}$ and therefore are non-ending, non-recurring.

The number sequence is $3\sqrt{25} = 3 \times 5 = 15$

Rational amount since it is classified as $\frac{p}{q}$ . $\frac{-11}{151}$ is really a rational number.

$1.\overline{1.625}$ is a real function, since it does not end but repeats it.

The rational number $\sqrt {256} = 16$

Unreasonable number $\sqrt{141}$ .

7 0

3 years ago

Read 2 more answers

FInd the sum of the first 20 terms of the series 3+5+7+....?

melamori03 [73]

Answer:

Explanation:

I added everything together.

3 0

2 years ago

What is the distance between (6, 2) and (6, -5)? A.-7 units B.3 units C.7 units D.11 units

kaheart [24]

Hey there! The correct option is A. -7 units (see photo for more info)

You can see in the photo I provided that there are 7 spaces in between (6, 2) & (6, -5) & since -5 is negative, the number of units in be will be negative.

Hope this helps you!

God bless ❤️

xXxGolferGirlxXx