Answer:
✑ Question :
- Is ( 11 , 9 ) , ( 11 , 5 ) , ( 9 , 3 ) a function ?
No , it's not a function.
✎ Reason :
This is not a function because one element 11 of set A is associated to elements 9 and 5 of set B.
♨ Explore about function :
↪ Function is a special type of relation. It is the refinement of relation. In a relation from A to B , every element of set A should have only one ( distinct ) image in B to be a function. In other words , if no two different ordered pairs have the same first component , then it is a function.
Hope I helped!
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Answer:
10
Step-by-step explanation:
To find the value of n we can write:
(n + n + 3 + n + 4 + n + 5 + n + 6 + n + 8 + n + 10 + n + 12 + n + 15) / 9 = 11
(9n + 63) / 9 = 11
9n + 63 = 99
9n = 36
n = 4
The median is n + 6 which is 4 + 6 = 10.
Answer: Step-by-step explanation:
Step-by-step explanation:
The range of a function is the set of images associated with a given domains. As domain is a discrete set, the range can be determined by evaluating the function at each element in domain:
x = 0
x = 1
x = 2
x = 3
The range of r(x) is .
Place value is the value individual digit has in its location:
in order from higher to lower value, there is thousands, hundreds, tens, and
ones.
When you divide by 10, you are affecting (only once) every digit from its current
place value to the right.
For example 1000 divided by 10 = 100, you have relocated every digit to the
right, making the zero dissolve (or better yet, divided by a hidden and in this
case unusable comma).
