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Alinara [238K]
3 years ago
15

Find the output, y, when the input, , is 6.

Mathematics
1 answer:
alexira [117]3 years ago
6 0

Answer:

you can eat this then you will got answer

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Multiply (2x+3) (-x -2)
Marysya12 [62]

Answer:

-2x^{2} -7x-6

Step-by-step explanation:

(2x + 3) (-x - 2)

distribute first term, to the second term:

2x(-x) + 2x(-2) + 3(-x) + 3(-2)

multiply:

(-2x^{2}) + (-4x) + (-3x) + (-6)

-2x^{2} -4x-3x-6

combine the like terms:

-2x^{2} - 4x - 3x - 6

             -7x

-2x^{2} - 7x - 6

final answer :

-2x^{2} - 7x - 6

hope this helped !!

mark me brainliest :D

6 0
3 years ago
Calculator
Ludmilka [50]

Answer:

34

Step-by-step explanation:

42/21 = x/17

solve to get the answer

2 = x/17

2*17 = x/17 * 17

34 = x

5 0
3 years ago
PLEASE HELP MEE<br> I will give brainliest :)<br> Question in the picture
Anni [7]

Answer:

I got -11/15

Step-by-step explanation:

I did 3 (1)/(2)*(2)/(5)-5 (1)/(3)*(2)/(5)

7 0
3 years ago
Read 2 more answers
The braking distance, in feet of a car a Travling at v miles per hour is given.
irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

  • The braking distance at 25 mph, is approximately <u>63.7 ft.</u>
  • The braking distance at 55 mph,  is approximately <u>298.35 ft.</u>
  • The braking distance at 85 mph,  is approximately <u>708.92 ft.</u>

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.

At 25 mph, the braking distance is approximately <u>63.7 ft.</u>

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945  ft.s

D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.

At 55 mph, the braking distance is approximately <u>298.35 ft.</u>

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.

At 85 mph, the braking distance is approximately <u>708.92 ft.</u>

b. The speed of the car when the braking distance is 450 feet is given as follows;

450 = 2.6 + \dfrac{v^2}{22}

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ <u>98.211 ft./s</u>

Learn more here:

brainly.com/question/18591940

8 0
2 years ago
Please help ASAP! I will mark Brainliest! Please answer CORRECTLY! No guessing! Show your work!
Amanda [17]

Answer:

P represents the population in year 0

Step-by-step explanation:

The exponential growth function is f(x) = a (1 + r)^t, where a is the initial

amount (at t = 0), (1 + r) is the factor of growth , r is the rate of growth

in decimal ant is the time of growth

the function C(t) = P(1 + r)^t represents the population of

centerville at year t, where P is the initial population and r is the

rate of increase

If your investment is increased 10% annually, then that means

each year, your total has multiplied itself by 110% (the growth factor

is 1 + 10/100 = 1.1)

(1 + r) is the factor grows each year

C(t) = P(1 + r)^t

C depends on P(starting population) , r(the increasing rate and

t(the time in year)

r is the rate of increase means the percentage of increasing , then

0 < r < 1

r is not less than 0

P is the initial amount when t = 0

P represents the population in year 0

4 0
3 years ago
Read 2 more answers
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