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3 years ago

(!!15 points!!) Find the measure of arc BDC

Mathematics

2 answers:

pentagon [3]3 years ago

7 0

It could also be pi radians but it asks for degrees... that's weird. There must be an error

Paha777 [63]3 years ago

6 0

Answer:

180°

Half the circle (360°) is 180°

The central angle is also 180° and the arc is congruent to the measure of the central angle.

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Please help me with this thankyou

DerKrebs [107]

The answer would be 60

The first think you would need to do would simply 144. Which would be 12.

Then you are going to want to multiply-5 by 12.
Which would be 60.
With 12 as a positive number, being greater or to than 60 then will become a positive.

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3 years ago

What is the solution to the equation 4x - 6 = 22

alexandr402 [8]

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Dominik [7]

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3 years ago

QUICK!! TEN POINTS!! BRAINLIEST FOR WHOEVER GETS IT RIGHT!!

lara [203]

Answer:

(-2, -4.5)

Step-by-step explanation:

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3 years ago

Read 2 more answers

Find thhe remainder when 7^203 is divided by 4

Aleksandr [31]

Using the square-and-multiply approach, we have

$7^{203}=7\times(7^{101})^2$
$7^{101}=7\times(7^{50})^2$
$7^{50}=(7^{25})^2$
$7^{25}=7\times(7^{12})^2$
$7^{12}=(7^6)^2$
$7^6=(7^3)^2$
$7^3=7\times7^2$

and so, using the property that, if $a_1\equiv b_1\mod n$ and $a_2\equiv b_2\mod n$ , then $a_1a_2\equiv b_1b_2\mod n$ , we get

$7\equiv3\mod4$
$7^2\equiv9\equiv1\mod4$
$7^3\equiv7\times1\equiv7\equiv3\mod4$
$7^6\equiv9\equiv1\mod4$
$7^{12}\equiv1\mod4$
$7^{25}\equiv7\times1\equiv7\equiv3\mod4$
$7^{50}\equiv9\equiv1\mod4$
$7^{101}\equiv7\times1\equiv7\equiv3\mod4$
$7^{203}\equiv7\times9\equiv3\times1\equiv3\mod4$

4 0

3 years ago