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Thepotemich [5.8K]
3 years ago
14

8x + 3y +6 = 0 in standard form

Mathematics
2 answers:
tino4ka555 [31]3 years ago
8 0

Answer:

8x+3y+6=0

transfer 8x and 6 to the equal side which becomes

3y=-8×-6

Marina86 [1]3 years ago
5 0

Answer:

8x + 3y= -6

Step-by-step explanation:

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Sawyer fills 1/6 of his gas tank in 3/4 of a minute. How many minutes will it take Sawyer to fill his gas tank?
Radda [10]

Answer:

.75 * 6 = 4.5 minutes

Step-by-step explanation:

.75 is 3/4 multiply by 6 because 6/6 is a whole tank of gas.

Sawyers tank takes 4.5 minutes to be filled up.

5 0
2 years ago
Read 2 more answers
The difference of eighteen and a number is 3
Firdavs [7]

Answer:

15

Step-by-step explanation:

18-x=3

18-3=x

18-3=15

5 0
3 years ago
Special right traingles (30, 60, 90<br> 45, 45, 90
igor_vitrenko [27]

Answer:

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Step-by-step explanation:

3 0
3 years ago
Please be kind and help me on this question.<br> WARNING: only if your good at math thank you
AVprozaik [17]

Short Answer: The first three are absolutely true. Congruency is maintained if all you are doing is shifting the figure 8 spaces away. Since the figures are congruent, their corresponding parts are equal and the statements made are always true. That's the guiding principle.


A is true. See the short answer.


B is True. You have gone 8 units away. The distance between the old G and the new one is 8 units. This is not a congruency property but it is true because it is given. You haven't altered the shape or rotatated it.


C is true by conguency. You have just shifted things 8 units. You have maintained equality and you have maintained distance between corresponding parts.


That leaves D. If the figures are regular, that will be true. If they are not regular, non corresponding external angles cannot be guaranteed to be true.

7 0
3 years ago
What is (14x^2– 27x+9) / (7x-3)?<br><br> A. 7x-3<br> B. 2x-3<br> C. -211x+9<br> D. 2x-33
Yakvenalex [24]

Answer:

B. 2x - 3

Step-by-step explanation:

\rm \frac{ {14x}^{2}  - 27x + 9}{7x - 3}

\rm  =  \frac{ \cancel{(7x - 3)}(2x - 3)}{ \cancel{7x - 3}}

\boxed{ \rm   \bold{= 2x - 3}}

4 0
3 years ago
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