Givens
x + y = 3
x =6 - 4y
Solution
Use the top equation to substitute for x in the second equation.
x = 3 - y
Put this result into the second given equation and solve for y
3 - y = 6 - 4y Add 4y to both sides.
3 - y + 4y = 6 Combine on the left
3 + 3y = 6 Subtract 3 from both sides
3 - 3 + 3y = 6 - 3 Combine
3y = 3 Divide by 3
3y/3 = 3/3 Combine
y = 1
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x + y = 3 but y = 1
x + 1 = 3 Subtract 1 from both sides.
x + 1 - 1 =3 - 1
x = 2
Answer
x = 2
y = 1
7-2=5
17-16=1
You are trying to find the difference that equals 3 and is near those range of numbers.
The numbers are 11 and 14.
Answer:
190.
Step-by-step explanation:
Hello there I hope you are having a great day :)
Your Question, -4(2x + 4) > 8x + 64 Solve for X
1) Expand -8x-16>8x+64
2) Add 16 to both sides -8x-16+16>8x+64+16
3) Simplify -8x>8x+80
4) Subtract 8x from both sides -8x-8x>8x+80-8x
5) Simplify -16x>80
6) Multiply both sides -1 (Reverse the inequality) (-16x) (-1) >80 (-1)
7) Simplify 16x<-80
8) divide both sides by 16 16x/16 < -80/16
9) Simplify x < -5
This should be your answer x < -5
Hopefully that helps you :)
30 is the answer
i can help if need be
