The correct answer is the one on the top right corner.
 
        
             
        
        
        
Answer:
60 minutes for the larger hose to fill the swimming pool by itself
Step-by-step explanation:
It is given that,
Working together, it takes two different sized hoses 20 minutes to fill a small swimming pool.
takes 30 minutes for the larger hose to fill the swimming pool by itself
Let x be the efficiency to fill the swimming pool by larger hose
and y be the efficiency to fill the swimming pool by larger hose
<u>To find LCM of 20 and 30</u>
LCM (20, 30) = 60
<u>To find the efficiency </u>
Let x be the efficiency to fill the swimming pool by larger hose
and y be the efficiency to fill the swimming pool by larger hose
x = 60/30 =2
x + y = 60 /20 = 3
Therefore efficiency of y = (x + y) - x =3 - 2 = 1
so, time taken to fill the swimming pool by small hose = 60/1 = 60 minutes
 
        
             
        
        
        
-23 over 5 ÷ 11 over 5 
 -23 × 5 over 5 × 5 
 -115 over 55 
Therefore, your answer would be: -2 and 1 over 11
        
                    
             
        
        
        
The solution would
be like this for this specific problem:
sin ( x - ( pi / 7 ) ) = - sqrt ( 2 ) / 2 
 x - ( pi / 7 ) = - pi / 4 + 2n*pi or x - ( pi / 7 ) = (5pi / 4 ) + 2n*pi 
 x = ( pi / 7 ) - ( pi / 4 ) + 2n*pi or x = ( 5pi / 4 ) + ( pi / 7 ) + 2n*pi 
 x = ( - 3pi / 28 ) + 2n*pi 
<span>I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.</span>