All categories

3 years ago

Find (f/g) (x) and state the domain restriction. f (x) = 6x - 3 and g(x) = 12x^2 - 6x

Mathematics

1 answer:

Rufina [12.5K]3 years ago

8 0

9514 1404 393

Answer:

(f/g)(x) = 1/(2x)

x ≠ 1/2

Step-by-step explanation:

$(f/g)(x)=\dfrac{f(x)}{g(x)}=\dfrac{6x-3}{12x^2-6x}=\dfrac{6x-3}{2x(6x-3)}\\\\\boxed{(f/g)(x)=\dfrac{1}{2x}}\quad x\ne\dfrac{1}{2}$

The domain restriction x ≠ 1/2 comes from the requirement to prevent the denominator factor 6x-3 from being zero.

You might be interested in

7x+6>or equal to -(x-6)

WINSTONCH [101]

Answer:

x≥ 0

Step-by-step explanation:

7x+6 ≥ -(x-6)

Distribute the minus sign

7x+6 ≥ -x+6

Add x to each side

7x+x+6 ≥ -x+x+6

8x+6 ≥ 6

Subtract 6 from each side

8x+6-6 ≥ 6

8x≥ 0

Divide by 8

8x/8≥ 0/8

x≥ 0

3 0

3 years ago

If BC=2x-3 and AC=2x+10, find the length of AB

Anettt [7]

Answer:

Step-by-step explanation:

xcsddddssss

5 0

2 years ago

BRAINLEST

Debora [2.8K]

I believe it's cones, cylinders, and spheres, hope this really help, and good luck

7 0

3 years ago

Read 2 more answers

An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concen

devlian [24]

Answer:

(a) A 95% confidence interval for the population mean is [433.36 , 448.64].

(b) A 95% upper confidence bound for the population mean is 448.64.

Step-by-step explanation:

We are given that article contained the following observations on degrees of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:

420, 425, 427, 427, 432, 433, 434, 437, 439, 446, 447, 448, 453, 454, 465, 469.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = $\frac{\sum X}{n}$ = 441

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 14.34

n = sample size = 16

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.131 < $t_1_5$ < 2.131) = 0.95 {As the critical value of t at 15 degrees of

freedom are -2.131 & 2.131 with P = 2.5%}

P(-2.131 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.131) = 0.95

P( $-2.131 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.131 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X -2.131 \times {\frac{s}{\sqrt{n} } }$ , $\bar X +2.131 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $441-2.131 \times {\frac{14.34}{\sqrt{16} } }$ , $441+2.131 \times {\frac{14.34}{\sqrt{16} } }$ ]

= [433.36 , 448.64]

(a) Therefore, a 95% confidence interval for the population mean is [433.36 , 448.64].

The interpretation of the above interval is that we are 95% confident that the population mean will lie between 433.36 and 448.64.

(b) A 95% upper confidence bound for the population mean is 448.64 which means that we are 95% confident that the population mean will not be more than 448.64.

6 0

3 years ago

Angelo charges $30 to mow 1 yard. Which equation could be used to determine the total cost, y, for mowing x yards? A. y = x + 30

alexira [117]

Answer:

D. y=30x

Step-by-step explanation:

So x represents like say if he mowed 3 yards.

y=30(3)

Then y would equal 90

8 0

3 years ago

Read 2 more answers